1
$\begingroup$

In local class field theory, the reciprocity map is constructed by using the isomorphism ${\rm Br}(F)\simeq \mathbb{Q/Z}$, where $F$ is a local field and ${\rm Br}(F)$ is its Brauer group. The cohomological cup product $$ H^{0}({\rm Gal}(F^{\rm sep}/F),(F^{\rm sep})^{\times})\times H^{2}({\rm Gal}(F^{\rm sep}/F),\mathbb{Z})\longrightarrow {\rm Br}(F)$$ provides reciprocity map $F^{\times}\simeq H^{0}({\rm Gal}(F^{\rm sep}/F),(F^{\rm sep})^{\times})\longrightarrow {\rm Hom}(H^{2}({\rm Gal}(F^{\rm sep}/F),\mathbb{Z}),{\rm Br}(F))\simeq {\rm Gal}(F^{\rm ab}/F)$. For a finite field $\mathbb{F_{q}}$, we knew that $H^{2}({\rm Gal}(\mathbb{F_{q}^{\rm sep}/F_{q}}),\mathbb{Z})\simeq \mathbb{Q/Z}$. Recall that $\mathbb{Z}=K^{\rm top}_{0}(\mathbb{F}^{\rm sep}_{q})$ and $(F^{\rm sep})^{\times}\simeq K^{\rm top}_{1}(F^{\rm sep})$ where $F$ is a local field, we can predict that $H^{2}({\rm Gal}(F^{\rm sep}/F),K_{n}^{\rm top}(F^{\rm sep}))\simeq \mathbb{Q/Z}$ where $F$ is a $n$-dimensional local field. I have not shown this claim yet, but If this is true, I conjecture that we may be able to show higher class field theory by using cup product $$ H^{0}({\rm Gal}(F^{\rm sep}/F),K_{n}^{\rm top}(F^{\rm sep}))\times H^{2}({\rm Gal}(F^{\rm sep}/F),\mathbb{Z})\longrightarrow H^{2}({\rm Gal}(F^{\rm sep}/F),K_{n}^{\rm top}(F^{\rm sep})) \simeq \mathbb{Q/Z}. $$ So in this case, all I need is an isomorphism $H^{0}({\rm Gal}(F^{\rm sep}/F),K_{n}^{\rm top}(F^{\rm sep}))\simeq K_{n}^{\rm top}(F)$. This is clear when $n=1$. Ivan Fesenko proved that for a prime degree cyclic extension $L/F$ of a $n$-dimensional local field $F$, the invariant part $K_{n}^{\rm top}(L)^{{\rm Gal}(L/F)}$ is isomorphic to $K_{n}^{\rm top}(F)$.

Question. A finite Galois extension $E/F$ of $n$-dimensional local fields, is $0$-th cohomology $H^{0}({\rm Gal}(E/F),K_{n}^{\rm top}(E))$ isomorphic to $K_{n}^{\rm top}(F)$?

$\endgroup$

1 Answer 1

1
$\begingroup$

This is almost certainly false.

Check out

Y. Koya - A generalization of class formation by using hypercohomology (Invent Math 1990)

On the 3rd page (707 in the journal pagination) it is stated to be "well-known" that your question has a negative answer for ordinary Milnor K-groups. Koya only takes all the troubles in this article exactly because of the failure of this property.

I don't know a concrete counterexample off-hand, but I am sure that any counterexample can be translated to one for topological Milnor K-groups.

The idea of topological Milnor K-groups is that they throw away data which is arithmetically irrelevant anyway, so at least per yoga this should work.

I would suspect that $K_2^{top}(F)\rightarrow K_2^{top}(E)$ is not even injective for all finite extensions of $2$-local fields. For $K_2$ Milnor K-theory for a field is still the same as Quillen $K$-theory and the latter is known to fail Galois descent. Even if you use etale $K$-theory, this only gives you Galois descent on the level of the spectrum, not of an individual homotopy group.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .