7
$\begingroup$

Let $K$ be an algebraically closed field and let $A$ and $B$ be finite dimensional algebras over $K$. Let $e_1,\ldots, e_n$ be orthogonal primitive idempotents of $A$ summing to $1$ and $f_1,\ldots, f_m$ be orthogonal primitive idempotents of $B$ summing to $1$. Then the $e_i\otimes f_j$ form a set of orthogonal primitive idempotents of $A\otimes_K B$ summing to $1$. Moreover, $(A\otimes_K B)(e_i\otimes f_j)\cong (A\otimes_K B)(e_{i'}\otimes f_{j'})$ if and only if $Ae_i\cong Ae_{i'}$ and $Bf_j\cong Bf_{j'}$. Note that this need not hold if $K$ is not algebraically closed.

I know how to prove these things but I want to cite this in a paper I'm writing and couldn't find this spelled out in any of my usual references on finite dimensional algebras. I don't really want to put a proof in my paper as it is a bit far a field. Actually, what I want to use this for is to conclude that the basic algebra of $A\otimes_K B$ is the tensor product of the basic algebras of $A$ and $B$ (again with $K$ algebraically closed).

I would greatly appreciate any reference, particularly, to a book.

$\endgroup$
2
  • $\begingroup$ Perhaps try Pierce's Associative Algebras? $\endgroup$
    – Pedro
    Commented Aug 23, 2020 at 15:32
  • $\begingroup$ @PedroTamaroff, I didn't see anything in Pierce $\endgroup$ Commented Aug 23, 2020 at 18:30

1 Answer 1

5
$\begingroup$

A treatment of this can be found in chapter IV.11. in the book "Frobenius algebras I" by Skowronski and Yamagata with proofs in the case $A=B^{op}$. But the proofs work exactly the same in the general case with the exact same proofs so it can be used as a reference for the general case I think.

$\endgroup$
2
  • $\begingroup$ Thanks. I'll look at the book. It would be nice if the general case was stated since it is annoying to say they prove it in a special case but the same proof works. $\endgroup$ Commented Aug 23, 2020 at 16:51
  • $\begingroup$ If nobody can find a reference for the general case I will go with this one. $\endgroup$ Commented Aug 23, 2020 at 19:59

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .