3
$\begingroup$

Sorry in advance if my question doesn't have the level of this community.

I am studying this paper of Bondal and Van Den Bergh and in particular section 2. Generators and resolutions in triangulated categories.

As long as I was figuring out the definitions of "classically generated", "generated" and "compactly generated", I came up with the Theorem 2.1.2 of this paper which says that in a compactly generated category $\mathcal{C}$, a set of objects $\mathcal{E}\subset \mathcal{C}^{c}$ classically generates $\mathcal{C}^{c}$ if and only if it generates $\mathcal{C}$. For the proof I started to read the reffering paper by Neeman and successfully finished and understood it. But there are some problems of connecting the information of the 2 papers.

  1. First of all, while theorem 2.1.2 uses the notion of "generates" that Bondal and Van Den Bergh define, in Neeman's paper there is nowhere such a notion and maybe instead of this, he uses the notion of the smallest localising triangulated subcategory that contains a set of objects. I think that there is the following connection which I unfortunately can't prove $$\mathcal{R}\ \text {is the smallest localising triangulated subcategory that contains a set}\ R\subset \mathcal{C}^{c}\ \Leftrightarrow $$$$R^{\perp}=0 $$ where $R^{\perp}$ is defined as in Bondal's paper as a subcategory of $\mathcal{R}$ and $\mathcal{R}$ is the smallest localising triangulated subcategory that contains a set $R\subset \mathcal{C}^{c}$ as in Neeman's paper. I strongly think that this is true under the hypothesis that $\mathcal{R}\subset \mathcal{C}$ where $\mathcal{C}$ is compactly generated.
  2. If the 1. is true then I construct the proof of Theorem 2.1.2 in the following way: by lemma 2.2 in Neeman's Paper(in the main proof of theorem 2.1) we clearly have the implication $\mathcal{E}$ generates $\mathcal{C}$ $\implies$ $\mathcal{E}\subset \mathcal{C}^{c}$ classically generates $\mathcal{C}^{c}$. For the other direction we note that if the smallest localising triangulated subcategory that contains $\mathcal{C}^{c}$ is the whole $C$, then $\mathcal{C}$ consists of coproducts of objects in $\mathcal{C}^{c}$. Then it is easy, since $Hom(M,\bigoplus E_{i})\cong \bigoplus Hom(M,E_{i})$.

As it seems there is a problem of combining these two papers and any help will be accepted.

Edit: To be honest I hadn't found this post that has an answer from Leonid Positselski, so I reform my question: as the proof is for well-generated categories (a generalised notion of compact objects) and uses the Brown representability theorem for triangulated categories I was wondering if there is a simpler proof for compact objects without using it. Maybe the first proof before the introduction of well-generatedness by Krause and others.

$\endgroup$
2
  • $\begingroup$ Cross-posted on math.stackexchange $\endgroup$ Jun 30, 2020 at 10:18
  • $\begingroup$ Thank you very much for the comment Profesor @JeremyRickard.I also edited the post above. $\endgroup$ Jun 30, 2020 at 20:54

1 Answer 1

3
$\begingroup$

I agree that the various notions of 'generates' can be confusing. I think the following result may clarify what you are after (this can be found in Lemma 2.2.1 of 'Stable model categories are categories of modules' by Schwede and Shipley).

Let $\mathcal{C}$ be a triangulated category with infinite coproducts and let $\mathcal{P}$ be a set of compact objects. Then the following are equivalent:

(i) The smallest localizing subcategory of $\mathcal{C}$ containing $\mathcal{P}$ is $\mathcal{C}$.

(ii) An object $X \in \mathcal{C}$ is trivial if and only if $[P,X]_* = 0$ for all $P \in \mathcal{P}$ (in the language of the question, $\mathcal{P}^{\perp} = 0$).

Finally, we also have the following, due to Thomason:

Suppose $\mathcal{C}$ is a compactly generated triangulated category, and $\mathcal{A}$ is a set of compact objects, then $\mathop{Loc(A)} \cap \mathcal{C}^{c} = \mathop{Thick(A)}$.

Here $\mathop{Loc}(\mathcal{A})$ denotes the smallest localizing subcategory of $\mathcal{C}$ containing $\mathcal{A}$, and $\mathop{Thick}(\mathcal{A})$ denotes the smallest thick (epaisse in Bondal--Van Den Bergh) subcategory of $\mathcal{C}^c$ containing $\mathcal{A}$.

$\endgroup$
1
  • $\begingroup$ Thank you very much @Drew Heard for the answer.Actually,after your response and some reading of Lemma 2.2.1 of 'Stable model categories are categories of modules' by Schwede and Shipley i figured out that in particular lemma 1.7 of Neeman's paper gives what i wanted (as Schwede and Shipley explains but it was unclear to me in Neeman's paper) $\endgroup$ Jul 1, 2020 at 10:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.