2
$\begingroup$

Let $S \neq \emptyset$ and let $\big((E_s,\mathcal{T}_s)\big)_{s \in S}$ be a family of locally convex vector subspaces of the same vector space. Denote by $E_s^*$ the dual space of $(E_s,\mathcal{T}_s),$ that is, the vector space of all $\mathcal{T}_s$-continuous linear functionals on $E_s.$ Furthermore, we set $M := \bigcap_{s \in S} E_s.$

The goal is to characterize the dual space of $(M,\mathcal{T}_M)$, where $\mathcal{T}_M := \tau(\mathcal{T}_s \cap M: \,s\in S)$ denotes the smallest topology on $M$ that contains $\mathcal{T}_s \cap M$ for every $s \in S.$

Obviously, we have

\begin{equation} \text{lin span}\, \bigg(\bigcup_{s\in S} E_s^*|_M\bigg) \subset M^*, \end{equation}

where $E_s^*|_M$ denotes the set of all continuous linear functionals of $E_s^*$ restricted to $M.$

Question (general): Do we even have

\begin{equation} \text{lin span}\, \bigg(\bigcup_{s\in S} E_s^*|_M\bigg) = M^*\, ? \end{equation}

Question (specific): Is something known for the dual space of the intersection of Lebesgue spaces w.r.t. $\sigma$-finite measures? For example, let $\mu$ and $\nu$ be $\sigma$-finite measures, what is known about the dual of the quotient space $$ L_p(X,\mathcal{A},\{\mu,\nu\}) := \left(\mathcal{L}_p(X,\mathcal{A},\nu) \cap \mathcal{L}_p(X,\mathcal{A},\mu)\right) \, /\,\, [\mu+\nu], $$ equipped with the topology $\tau(\|\cdot\|_{\mu,p},\|\cdot\|_{\nu,p})?$ Here, $[\mu+\nu]$ is the subspace of all functions $f$ such that $f = 0$ almost surely w.r.t. $\mu+\nu$ and $\mathcal{L}_p(X,\mathcal{A},\nu)$ denotes the set of all $\mathcal{A}$-measurable functions that are $p\text{th}$ power $\nu$-integrable.

$\endgroup$
4
  • 2
    $\begingroup$ If the measures $\mu$ and $\nu$ are not equivalent (in the sense that they have different negligable sets) it is not clear what you mean by the intersection -- if you take the definition of the Lebesgue spaces (equivalence classes of a.e. equal functions) literally the intersection would be empty. $\endgroup$ Apr 8, 2020 at 20:18
  • $\begingroup$ Thanks for your comment. I've edited the question. $\endgroup$
    – Henning
    Apr 8, 2020 at 20:45
  • 1
    $\begingroup$ Surely "are $p$-times $\nu$-integrable" should be "have $\nu$-integrable $p$th power"? Also, what is the common vector space in which $\mathcal L_p(X, A, \nu)/[\mu + \nu]$ and $\mathcal L_p(X, A, \mu)/[\mu + \nu]$ both live? $\endgroup$
    – LSpice
    Apr 8, 2020 at 23:16
  • $\begingroup$ If $\mathcal{L}(X,\mathcal{A})$ denotes the space of all $\mathcal{A}$-measurable functions, the common vector space is $\mathcal{L}(X,\mathcal{A})\,/\,[\mu + \nu].$ $\endgroup$
    – Henning
    Apr 9, 2020 at 14:15

2 Answers 2

2
$\begingroup$

Let me suggest a slightly more structured situation in a first attempt at a solution: I would consider the one where we have lcs’s $E_0$ and $E_\infty$ with $E_0 \subset E_s\subset E_\infty$ and each of the inclusions continuous with dense images, in addition with the $E_s$ Banach spaces. In this case the dual of the intersection is indeed the linear hull of the dual spaces. The question of how many of these assumptions are superfluous would require more thought.

The special case you mention fits into this scheme (assuming $p$ is finite for simplicity). One can use a suitable space of step functions as $E_0$ and the measurable functions as $E_\infty$ (in this case allowing the latter to be a non locally convex tvs).

$\endgroup$
4
  • $\begingroup$ Could you add a reference or an argument for the fact that the dual space of the intersection is the linear hull of the dual spaces? Right now, I can't see why this is the case. $\endgroup$ Apr 8, 2020 at 12:21
  • $\begingroup$ Thanks for your contribution. However, I am not sure if the special case fits into the scheme you have described. The intersection of the two Lebesgue spaces is w.r.t. two $\sigma$-finite measures and not w.r.t. the exponents. $\endgroup$
    – Henning
    Apr 8, 2020 at 12:59
  • 2
    $\begingroup$ @JochenGlueck It is helpful to consider the diagonal map which, for two spaces, is $Delta: X\cap Y \to X\times Y$, $x\mapsto (x,x)$. You certainly know the dual of $X\times Y$ and you can calculate the transposed of the diagonal map. The case described by user131781 is particularly nice because then the Image of $\Delta$ equals the kernel of the difference map $d: X\times Y \to E_\infty$, $(x,y)\mapsto x-y$, i.e, you have a short exact sequence $0\to X\cap Y \to X\times Y \to Image(d)\to 0$. $\endgroup$ Apr 8, 2020 at 20:27
  • $\begingroup$ @JochenWengenroth: That's a nice argument! Thank you very much. $\endgroup$ Apr 9, 2020 at 0:15
0
$\begingroup$

$\DeclareMathOperator\span{span}$Let $M$ be a set of finite measures on $(X,\mathcal{A})$ and consider $$ L_p(X,\mathcal{A},M) := \left(\bigcap_{\mu \in M} \mathcal{L}_p(X,\mathcal{A},\mu) \right) \, / \, [M] $$ for some $p\in\mathopen]1,\infty\mathclose[.$ Let $q\in\mathopen]1,\infty\mathclose[$ such that $1/p + 1/q = 1$. Then, the dual space of $(L_p(X,\mathcal{A},M),\tau(\|\cdot\|_{\mu,p} : \mu \in M))$ is given by $$ L_p(X,\mathcal{A},M)^* = \span \left( \bigcup_{\mu\in M} \bigl\{ (\cdot,g)_\mu|_{L_p(X,\mathcal{A},M)} : g \in \mathcal{L}_q(X,\mathcal{A},\mu)\, / \, [M]\bigr\} \right). $$

Proof (similar to Satz II.2.4 in Werner (2018) "Funktionalanalysis", Springer-Verlag): Clearly, for each $\mu \in M$ and each $g \in \mathcal{L}_q(X,\mathcal{A},\mu)$ we have that $(\cdot,g)_\mu|_{L_p(X,\mathcal{A},M)}$ is a continuous linear function on $L_p(X,\mathcal{A},M)$.

Conversely, let $f^* \in L_p(X,\mathcal{A},M)^*$ and define $$ \nu(A) := f^*(\mathbb{1}_A) \quad A \in\mathcal{A}. $$ Then, $\nu$ is a signed measure. Since $f^*$ is $\tau(\|\cdot\|_{\mu,p} : \mu \in M)$-continuous there are a finite set $F \subset M$ and a positive $L > 0$ such that $$ |f^*(g)| \leq L \max \{ \|g\|_{\mu,p} : \mu \in F\} $$ for all $g \in L_p(X,\mathcal{A},M),$ which yields that $\nu \ll \sum_{\mu \in F} \mu$. According to the Radon–Nikodym theorem there is a density $h$ of $\nu$ w.r.t. the finite measure $\sum_{\mu \in F} \mu$, that is, $$ f^*(g) = \int g h \, \mathrm{d} (\textstyle{\sum_{\mu \in F} \mu}) $$ for all $g \in L_{\infty}(\sum_{\mu \in F} \mu)$. Then, one can show that $h \in \mathcal{L}_{q}$ (see for example proof of Satz VIII.2.3 in Werner (2018)) and $f^* = \sum_{\mu \in F} (\cdot,h)_\mu|_{L_p(X,\mathcal{A},M)}$ on $L_p(X,\mathcal{A},M)$ since $L_{\infty}(\sum_{\mu \in F} \mu)$ is dense in $L_{p}(\sum_{\mu \in F} \mu)$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.