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As far as I know, it is unknown whether Thompson's group F has Yu's Property A (that is, whether it is exact) or not. See for instance this MO question. The question is said to be open at several places in the litterature, but these references are several years old.

I would like to know if someone is aware of a recent development. Thanks for your help !

For the definition of Property A, see G. Yu, Invent. math. 139 (2000), 201-240.

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    $\begingroup$ Last week I went to a colloquium talk by Jan Spakula in which I believe he stated that this was unknown. However, I did not take notes so I cannot guarantee that I remember correctly what he said. $\endgroup$ Nov 25, 2019 at 11:22
  • $\begingroup$ By the way Google Scholar or MathSciNet or MathZentralblatt can quickly list papers quoting those asking such a question. $\endgroup$
    – YCor
    Nov 25, 2019 at 19:58

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It is unknown. I (and some others) believe it is as hard as amenability. There were two approaches to this problem. One was discussed in Arzhantseva, Guba, Sapir, Metrics on diagram groups and uniform embeddings in a Hilbert space. Using that approach one would need to construct an embedding of $F$ into a Hilbert space with compression function $\gg \sqrt{n}$. That approach was killed in Gournay's The Liouville property and Hilbertian compression (Numdam) where it was proved that the compression function cannot exceed $\sqrt{n}$. Another approach from Dranishnikov and Sapir's On the dimension growth of groups uses the so-called dimension growth. We hoped that the dimension growth of $F$ is subexponential which would imply $A$ (see Ozawa, Metric spaces with subexponential asymptotic dimension growth). But it turned out to be not quite the case, although see this Corrigendum to “On the dimension growth of groups” [J. Algebra 347 (1) (2011) 23–39], by Dranishnikov and Sapir. The idea of using various dimension growth functions is still alive though. See, for example, Dranishnikov and Zarichnyi, Asymptotic dimension, decomposition complexity, and Haver's property C

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    $\begingroup$ It would be nice if you use the link option rather than leaving several lines of link visible. $\endgroup$
    – YCor
    Dec 3, 2019 at 10:12
  • $\begingroup$ Somebody replaced links by the same links without asking my pernission. I changed it back. $\endgroup$
    – user6976
    Dec 14, 2019 at 23:47
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    $\begingroup$ @YCor now that the user is gone, and some of the links were actually broken, I took the liberty of fixing it, even without "permission". $\endgroup$
    – David Roberts
    Nov 22, 2021 at 2:23

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