Suppose that $X$ is a complex algebraic variety, i.e. it is integral, separated, and of finite-type over $\mathbb{C}$. Let $\mathfrak{g}$ be a finite-dimensional complex Lie algebra.
Suppose that $\mathfrak{g}$ acts on $X$, i.e. we have a homomorphism $\phi:\mathfrak{g}\to \mathrm{Vec}(X)$, where $\mathrm{Vec}(X)$ is the Lie algebra of vector fields on $X$. Suppose further that for every closed point $x\in X$, the canonical morphism $$ \mathfrak{g}\to T_xX$$ is surjective. This should be the way to say the action is 'homogeneous'. My question is: does this imply $X$ is smooth? Or at least that the tangent sheaf is locally free? Feel free to assume $X$ is, say, normal if that is necessary.