41
$\begingroup$

The title is a quote from a Jim Holt article entitled, "The Riemann zeta conjecture and the laughter of the primes" (p. 47).1 His example of a "long-standing conjecture" is the Riemann hypothesis, and he is cautioning "those who blithely assume the truth of the Riemann conjecture."

Q. What are examples of long-standing conjectures in analysis that turned out to be false?

Is Holt's adverb "often" justified?


1 Jim Holt. When Einstein Walked with Gödel: Excursions to the Edge of Thought. Farrar, Straus and Giroux, 2018. pp.36-50. (NYTimes Review.)

$\endgroup$
16
  • 7
    $\begingroup$ In brief, the adjective is certainly not easily justified. Nor perhaps is there much point in addressing the population of those who blithely assume RH. Looks like an educated non-fiction writer's good-faith construction. $\endgroup$ Commented Jul 25, 2018 at 23:40
  • 8
    $\begingroup$ Re "believing" in RH: what impresses me more than the (seemingly) solemn cautionary declamation of Jim Holt (addressing whom exactly?) is the story of the Zagier-Bombieri wager. According to du Sautoy's book The Music of the Primes, Don Zagier, number theorist non pareil, moved from a position of semi-skepticism/agnosticism about the truth of RH to one of firm belief, after he lost his bet with Bombieri that the first 300 million non-trivial zeroes would yield one off the critical line (he had thought the odds were about 50-50). Of all the conjectures to warn about... $\endgroup$ Commented Jul 26, 2018 at 0:43
  • 3
    $\begingroup$ The Bieberbach conjecture was a long-standing conjecture in analysis which turned out to be true. $\endgroup$
    – bof
    Commented Jul 27, 2018 at 2:26
  • 5
    $\begingroup$ In commenting below Mark S's answer, I'm led to wonder how important Holt's essay is to the content of the question. At the risk of seeming very rude: I'm sort of tempted to ignore the question below the gray box, since I don't imagine Holt has much idea of what he's talking about when he speaks of analysis versus algebra, and there's not much point trying to figure out whether whatever he thinks he's saying is justified. Whatever he thinks analysis (and its scope) is, it's likely to be pretty different from what mathematicians understand it to mean. $\endgroup$ Commented Jul 28, 2018 at 14:30
  • 4
    $\begingroup$ @HarryGindi There's the old Harry I used to know! ;-) $\endgroup$ Commented Jul 29, 2018 at 22:15

6 Answers 6

73
$\begingroup$

I don't know about analysis in general, but I think it's definitely fair to say "often" in functional analysis. My feeling is that we have a solid, thorough, elegant body of theory which usually leads to positive solutions rather quickly, when they exist. (The Kadison-Singer problem is a recent exception which required radically new tools for a positive solution.) Problems that stick around for a long time tend to do so not because there's a complicated positive solution but because there's a complicated counterexample. That's a gross overgeneralization but I think there's some truth to it.

The first examples I can think of are:

  • every separable Banach space has the approximation property and has a Schauder basis (counterexample by Enflo)

  • every bounded linear operator on a Banach space has a nontrivial closed invariant subspace (counterexamples by Enflo and Read)

  • every infinite dimensional Banach space has an infinite dimensional subspace which admits an unconditional Schauder basis (counterexample by Gowers and Maurey)

  • every infinite dimensional Banach space $X$ is isomorphic to $X \oplus \mathbb{R}$; if $X$ and $Y$ are Banach spaces, each linearly homeomorphic to a subspace of the other, then they are linearly homeomorphic (counterexample by Gowers)

I can't resist also mentioning some examples that I was involved with.

  • Dixmier's problem: every prime C*-algebra is primitive (counterexample by me)

  • Naimark's problem: if a C*-algebra has only one irreducible representation up to unitary equivalence, then it is isomorphic to $K(H)$ for some Hilbert space $H$ (counterexample by Akemann and me)

  • every pure state on $B(l^2)$ is pure on some masa (counterexample by Akemann and me)

  • every automorphism of the Calkin algebra is inner (counterexample by Phillips and me)

The last three require extra set-theoretic axioms, so the correct statement is that if ordinary set theory is consistent, then it is consistent that these counterexamples exist. Presumably all three are independent of the usual axioms of set theory, but this is only known of the last one, where the consistency of a positive solution was proved by Farah.

$\endgroup$
9
  • 8
    $\begingroup$ this is a very nice collection of examples! But I'd wager that these are all wildly out-of-scope for the actual comment of the writer. Maybe they are indeed relevant to the OP, but this may be one of those times where the (educated?) layperson's question only accidentally stimulates genuine mathematical discussion. Not a bad thing! :) $\endgroup$ Commented Jul 26, 2018 at 0:28
  • 12
    $\begingroup$ @paulgarrett My guess is that RH is also out-of-scope for the writer, in terms of any real understanding of its import. (The only difference is that he's heard of it.) So I'd say anything is fair game. Your answer and Nik's are good ones. $\endgroup$ Commented Jul 26, 2018 at 1:12
  • 3
    $\begingroup$ I think this answer is likely true and certainly very useful, in that it can productively modify one's overall view/approach to functional analysis. Thanks, Nik! $\endgroup$
    – Jon Bannon
    Commented Jul 27, 2018 at 1:06
  • 1
    $\begingroup$ @JonBannon and Nik: perhaps this is why there is the free group factor problem rather than the free group factor conjecture :) Although I note that we have the Connes embedding problem yet the QWEP conjecture ... $\endgroup$
    – Yemon Choi
    Commented Jul 30, 2018 at 0:54
  • 1
    $\begingroup$ @NikWeaver and YemonChoi: Kadison personally told a group of us at lunch that von Neumann asked him the question. I can't recall if it appears in the MvN papers, does it? $\endgroup$
    – Jon Bannon
    Commented Jul 30, 2018 at 16:00
48
$\begingroup$

If RH is "analysis", then surely Littlewood's 1914 theorem that $\pi(x)$ (the prime counting function) and $\mathrm{li}(x)$ (the logarithmic integral) alternate in size infinitely often... despite all numerical evidence at the time indicating that $\pi(x)\le \mathrm{li}(x)$.

Part of the point is that the first reversal only occurs at a rather large number. S. Skewes, a student of Littlewood, gave an effective bound in 1933 assuming RH, and a better one in 1955 unconditionally, ... both of which were ridiculously large numbers. (Just search on "Skewes' number" to see details...)

Similarly, some regularities in the behavior of $\zeta(s)$ do only "kick in" when $\log\log(\Im(s))$ is large... which we will never appraise numerically. Dunno whether this is analysis, but it is fairly genuine mathematics of some sort, and may perhaps illustrate the possibility that phenomena do occur outside the range of direct (with or without computers, quantum or not) observation (by humans). In particular, even sophisticated numerical simulation cannot reach large $\log\log T$, so the conclusions that we draw (e.g., A. Odlyzko's and other's computation of zeros of zeta up to human-enormous heights) could potentially be ... meaningless?

(In a different way, the issues raised by Nik Weaver are somewhat similar, in that they arise from palpable issues, but whose abstractions inadvertently involve phenomenological entities surprisingly beyond our easy capacity.)

$\endgroup$
2
  • 4
    $\begingroup$ I love this phrase: "phenomenological entities surprisingly beyond our easy capacity"! $\endgroup$ Commented Jul 26, 2018 at 21:51
  • $\begingroup$ @JosephO'Rourke, :) $\endgroup$ Commented Jul 26, 2018 at 21:52
30
$\begingroup$

The Riemann hypothesis is a conjecture in both analysis and number theory. Someone who tries to undermine it necessarily has to ignore the latter part or to declare it irrelevant. I am not suggesting that it is true (I do not know), only that it becomes more plausible when you take into account that its violation implies a sort of conspiracy between primes and that there are function field analogs which are actually proven.

Once we look at the conjecture from this angle it is arguably unique, and no examples from analysis make a big point.

$\endgroup$
9
$\begingroup$

In another vein, taking the question seriously, etc.:

Let's consider the intermediate value theorem: a (continuous?) function takes every intermediate value, etc. Obviously true, when we believe that functions are things whose graphs we can (easily) draw. But, false, with introduction of not-continuous functions. But, then, again, it's ok when we add that qualifier.

Similarly, the mean value theorem: if $u'=0$, then $u$ is constant. Obviously true. Well, problems with saying what the derivative of a not-so-nice function is... distributions/generalized functions... But, in the end, if a distribution has derivative(s) zero, it is (integrate-against) a constant.

Whew!

Similarly, we can go through dialectics about integrals...

Perhaps even more substantially, the early 20th-century Polish school of set theory and real analysis looked at many situations where a hypothetical simplicity of description of subsets of $\mathbb R$ really needed the continuum hypothesis... or more. I'm insufficiently expert to discuss those things, but am aware of them.

$\endgroup$
7
$\begingroup$

With $\mu(k)$ is the Möbius function, the Mertens conjecture states that the Mertens function

$$M(n)=\sum_{1\le k\le n} \mu(k)$$

is bounded below above as $$|M(n)|\le \sqrt{n}$$

The conjecture lasted 100 years, from 1885 to 1985, when it started to crumble with the work of Andrew Odlyzko and Herman te Riele.

$\endgroup$
5
  • 2
    $\begingroup$ Yeah, this is a good example inasmuch as it relates to RH, but it'd be weird to consider this as "belonging to analysis" (even if it's not obviously not analysis). I can't tell if this is the sort of answer the OP is looking for. $\endgroup$ Commented Jul 28, 2018 at 14:11
  • 1
    $\begingroup$ Agreed. Reading Holt's (otherwise well-versed) article, it might be an example he had in mind. But there's another question lurking in Holt's essay... Are conjectures like Broadway plays, obeying Gott's Copernican principle? Are long-standing conjectures more likely to be unproven in the distant future? $\endgroup$
    – Mark S
    Commented Jul 28, 2018 at 16:52
  • $\begingroup$ Despite all the negativity in my comments in this thread, I agree that Holt's article is stimulating and well written. Regarding that question... yes, maybe, I guess?? Feels like an angels on the head of a pin question. :-) $\endgroup$ Commented Jul 28, 2018 at 17:27
  • $\begingroup$ Was I wrong to read this as a fine retort to Holt’s flip side that “long-standing conjectures in [¿not-analysis?] (like Fermat's theorem) typically turn out to be true”? (BTW: bounded above.) $\endgroup$ Commented Jul 29, 2018 at 21:32
  • $\begingroup$ @FrancoisZiegler thanks, embarrassed for the mistake. I suspect, without any evidence, that Holt might have used "analysis" as in "analytic number theory." To me and my naivety, Littlewood's theorem mentioned by paul garrett and Odlyzko and te Riele's theorem are of the same character, but are arguably not analysis as in Nik Weaver's answer along with paul's other answer. $\endgroup$
    – Mark S
    Commented Jul 29, 2018 at 23:29
3
$\begingroup$

Fuglede's conjecture was open for 30 years (1974-2004) only to be proven false by T. Tao for dimensions $d\geq 5$ with a counter-example arising from a set with an exponential orthonormal basis (a spectrum) in a finite abelian group which does not tile by translation. Interestingly, the largest dimension for which the conjecture is open now is $d=2$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .