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I'm interested in the question of given a differentiable and bounded function $f(\vec{x})$ (over a single variable or multiple variables, over a bounded domain $D$), finding a pair of polynomials $p_1(\vec{x})$ and $p_2(\vec{x})$ such that

$p_1(\vec{x}) \leq f(\vec{x}) \leq p_2(\vec{x}) ~~ \forall \vec{x} \in D $.

Ideally the polynomials $p_1$ and $p_2$ are defined as a linear combination of a few polynomials from some polynomial basis, and the bounds can be made arbitrarily tight by including more basis elements.

Any well studied objects of this sort would be ideal, I've looked at some basic polynomial approximation techniques but they only provide approximations (which can be re-purposed for bounds), but if there are any literature concerning just the bounds it would be a good starting point.

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    $\begingroup$ Finding such polynomials is possible if and only $f$ is bounded, and in this case you can use constant polynomials for $p_1$ and $p_2$. Nonconstant polynomials can only become necessary if you need the polynomial bounds to be good in some sense. If this is the case, please provide more details. $\endgroup$ Commented Sep 22, 2014 at 20:42
  • $\begingroup$ thanks, I've changed my statement, is it more clear now? $\endgroup$
    – Evan Pu
    Commented Sep 22, 2014 at 20:58
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    $\begingroup$ It's more clear now. But it seems to be equivalent with estimating functions uniformly with polynomials: if you estimate the functions $f\pm\epsilon$ with error $\epsilon$, you get $f$ tightly between two polynomials. $\endgroup$ Commented Sep 22, 2014 at 21:04
  • $\begingroup$ that sounds reasonable. what class of polynomials would you recommend? I was looking at Tchebychev polynomials but apparently they do not generalize to multiple dimentions (? is that the case) $\endgroup$
    – Evan Pu
    Commented Sep 22, 2014 at 21:27

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Let me turn my comments into an answer. I originally thought that the question would be off-topic here, so I chose not to give a full answer.

Let $f:D\to\mathbb R$ be any function on a bounded domain $D$. If there are polynomials $p_1,p_2$ so that $p_1\leq f\leq p_2$ on $D$, then $f$ is bounded. On the other hand, if $f$ is bounded, you can use constant polynomials for $p_1$ and $p_2$. Thus such bounding polynomials exist if and only if $f$ is bounded.

Estimating a continuous function on $\bar D$ arbitrarily tightly by polynomials is possible. (See this proof, for example.) This problem is actually equivalent with estimating function uniformly with polynomials: Tight polynomial upper and lower bounds provide a good polynomial approximation of $f$. In the other direction, if you estimate the functions $f\pm\epsilon$ with error $\epsilon$, you get polynomials above and below $f$ with distance at most $2\epsilon$ to it. (You can actually choose $p_2=p_1+2\epsilon$ if you do it like this.)

I am not an expert on polynomial approximation, so I can't recommend any literature. But there is certainly literature on polynomial approximation, and with the above argument you can turn polynomial approximation into polynomial bounds.

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