A circular triangle is a closed simple curve in the Euclidean plane $\mathbb{R}^2$ that can be expressed as the union of three circular arcs. Data naturally associated with such a figure includes:
- the edge lengths $\ell_i$,
- the edge curvatures $\kappa_i$, and
- the interior angles $\theta_i$
(for $i \in {1,2,3}$). In English, surprisingly little seems to have been written about these creatures. Mathworld provides some pointers, with perhaps the most useful reference being Area of Common Overlap of Three Circles. However, this investigation is a bit brute force/trigonometric/algorithmic, which makes it hard to get a clean picture of what's really going on in the "space of circular triangles." A few natural questions:
Question 1: What's a (nice) way to characterize data $\theta_i$, $\ell_i$, $\kappa_i$ that describes a valid circular triangle?
For instance, when the curvatures $\kappa_i$ are all zero (i.e., just a standard Euclidean triangle), the necessary and sufficient conditions are of course that the angles sum to $\pi$ and the lengths satisfy the triangle inequality. What about the general case? One can of course express, say, $\theta$ in terms of $\ell$ and $\kappa$, but the expressions get rather nasty. A related question is:
Question 2: Can all circular triangles be expressed as the image of geodesic triangles from some "nice" space under some "nice" map?
For instance, one can study the subset of circular triangles coming from spherical geometry (via stereographic projection) or hyperbolic geometry (via the Poincaré model). What about the rest?
If a global description is too nasty, I'd be willing to settle for a more local characterization:
Question 3: Suppose $\theta_i,\ell_i,\kappa_i$ describe a valid circular triangle. Generically, how can one vary this data so that the triangle remains valid? (Morally: what does the "tangent space" look like? What's its dimension?)
Finally, and more generally:
Question 4: Is there another name for this object? What else is known?
Any pointers are appreciated. Thanks!