3
$\begingroup$

As we know,if G is simple and ︱G︱=︱PSL(2,q)︱,then G is isomorphic to PSL(2,q).My question is if there is a character free proof for that.If there is one,how to do it?

$\endgroup$

2 Answers 2

8
$\begingroup$

There is a proof when q is a prime, due to Frobenius. I give a somewhat simplified version of it in a note that will appear in the American Mathematical monthly this October. (See my question 61348). The general problem seems, as has been noted, far less tractable.

$\endgroup$
3
$\begingroup$

See Borcherds' answer to a related question:

Number of finite simple groups of given order is at most 2 - is a classification-free proof possible?

He mentions that "It is usually extraordinarily difficult to prove uniqueness of a simple group given its order, or even given its order and complete character table." I expect the answer to your question is no, there is no simple proof and in particular, no proof that is genuinely character-free.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.