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How does the spectra of $DU$ change when $D$ runs over all diagonal unitary matrices? Here $U$ is a fixed unitary matrix. Precisely, let spec$(X)$ be a set of eigenvalues of $X$. For a unitary matrix $U$ let $$ S_U=\{ \mbox{spec}(DU)\;|\;D\mbox{ runs over all diagonal unitary matrices}\}. $$ Clearly, $S_U$ depends on $U$. Two examples:

  1. if $U$ is diagonal then spec($DU$) run over all possibilities: $S_U=({\mathbb C}_1)^n$, where ${\mathbb C}_1$ is the set of complex numbers of norm $1$ and $n$ is the size of $U$.

  2. Let $U$ be a cyclic permutation, that is
    $$ U=\left(\begin{array}{cccc} 0 & 0 & 0\dots\dots & 1\\\ 1 & 0 & 0\dots\dots & 0\\\ 0 & 1 & 0\dots\dots & 0\\\ \dots & \dots & \dots\dots\dots &\dots \\\ \end{array}\right). $$ Then $S_U=\{\{wa,w^2a,w^3a,...,w^na\}\;\;|\;\;a\in{\mathbb C}_1,\;w \mbox{ is primitive root of 1}\}$

Is something known about $S_U$ in general?

What is $S_U$ for

a) random $U$

b)for which $U$ $S_U$ looks like in example 2.

c) some concrete $U$, say $U$ being a finite Fourier transform matrices?

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  • $\begingroup$ How are you ordering your eigenvalues ? $\endgroup$ Jan 10, 2013 at 9:31
  • $\begingroup$ @ Michael I have not notice your comment before. I just consider it as a set... About b). Let $n$ be "very large" Then in example 2) al matrices $DU$ have "very small" spectral gaps. So, the question: for which $U$ all $DU$ have small maximal spectral gap? As $\\{DU\\}$ may be considered as a point in the flag manifold, one could try to relate this gap with a Reimann distance on the flag manifold.... $\endgroup$ Jan 24, 2013 at 18:56

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