36
$\begingroup$

There are several theorems I know of the form "Let $X$ be a locally ringed space obeying some condition like existence of partitions of unity. Let $E$ be a sheaf of $\mathcal{O}_X$ modules obeying some nice condition. Then $H^i(X, E)=0$ for $i>0$."

What is the best way to formulate this result? I ask because I'm sure I'll wind up teaching this material one day, and I'd like to get this right.

I asked a similar question over at nLab. Anyone who really understands this material might want to write something over there. If I come to be such a person, I'll do the writing!


Two versions I know:

(1) Suppose that, for any open cover $U_i$ of $X$, there are functions $f_i$ and open sets $V_i$ such that $\sum f_i=1$ and $\mathrm{Supp}(f_i) \subseteq U_i$. Then, for $E$ any sheaf of $\mathcal{O}_X$ modules, $H^i(X,E)=0$. Unravelling the definition of support, $\mathrm{Supp}(f_i) \subseteq U_i$ means that there exist open sets $V_i$ such that $X = U_i \cup V_i$ and $f_i|_{V_i}=0$.

Notice that the existence of partitions of unity is sometimes stated as the weaker condition that $f_i$ is zero on the closed set $X \setminus U_i$. If $X$ is regular, I believe the existence of partitions of unity in one sense implies the other. However, I care about algebraic geometry, and affine schemes have partitions of unity in the weak sense but not the strong.

(2) Any quasi-coherent sheaf on an affine scheme has no higher sheaf cohomology. (Hartshorne III.3.5 in the noetherian case; he cites EGA III.1.3.1 for the general case.) There is a similar result for the sheaf of analytic functions: see Cartan's Theorems.

I have some ideas about how this might generalize to locally ringed spaces other than schemes, but I am holding off because someone probably knows a better answer.


It looks like the answer I'm getting is "no one knows a criterion better than fine/soft sheaves." Thanks for all the help. I've written a blog post explaining why I think that fine sheaves aren't such a great answer on non-Hausdorff spaces like schemes.

$\endgroup$
4
  • $\begingroup$ Dear David, I don't quite understand the statement of (1). There seem to no conditions stated that involve the $V_i$; so how do conclude that $f_{| V_i}$ vanishes? Maybe $X = U_i \cup V_i$ is a condition, not a conclusion? $\endgroup$
    – Emerton
    Commented Jan 12, 2010 at 18:32
  • $\begingroup$ @Emerton The statement "$\mathrm{Supp}(f) \subset U$" is equivalent to "there exists an open set $V$ such that $X = U \cap V$ and $f|_V=0$." I'll see if I can make this clearer. $\endgroup$ Commented Jan 12, 2010 at 19:01
  • $\begingroup$ @Anweshi: that's certainly relevant. In particular, there is a nice idea there of using looking at the sheaf $End(E)$ instead of some ambient sheaf of commutative rings. But I worry about two things. (1) Fine sheaves are "usually only used over paracompact Hausdorff spaces": so not affine schemes. $\endgroup$ Commented Jan 12, 2010 at 19:05
  • $\begingroup$ I'll unpack my second worry as an edit up above; it's overflowing the character limit. $\endgroup$ Commented Jan 12, 2010 at 19:08

3 Answers 3

15
$\begingroup$

Although we clearly all have more or less the same answers, here is how I like to organize things.

I) Let $\mathcal F$ be a sheaf of abelian groups on the topological space $X$. It is said to be soft if every section $s \in \Gamma (A,\mathcal F)$ over a closed subset $A\subset X$ can be extended to $X$. Notice carefully that the definition of $s$ is NOT that it is the restriction to $A$ of some section of $\mathcal F$ on an open neighbourhood of $A$ [but that it is an element $ s\in \prod \limits_{x\in X} \mathcal F_x$ satisfying some more or less obvious conditions]

II) Consider the following condition on the [not necessarily locally] ringed space $(X, \mathcal O)$ :

The space $X$ is metrizable and given an inclusion $A\subset U \subset X$ with $A$ closed and $U$ open there exists a global section $s\in \Gamma (X,\mathcal O)$ such that $s|A=1$ and $ s|X \setminus U=0 \quad \quad (SOFT)$.

We then have the

$\textbf{Theorem }$ : If the ringed space satisfies (SOFT), then every sheaf of $\mathcal O_ X -Modules$ is soft.

III) A metrizable space endowed with its sheaf of continuous functions satisfies $(SOFT)$. A metrizable differential manifold endowed with its sheaf of smooth functions satisfies $(SOFT)$.

IV) On a metrizable space every soft sheaf is acyclic

Put together these results yield all standard acyclicity results on functions,vector bundles, distributions,etc.

It is interesting to notice that you use partitions of unity only once: in the proof of III). But never more afterwards; you just check that your sheaves are $\mathcal O -Modules$. I like this approach (which I learned from Grauert-Remmert) more than the usual one, where a proof of acyclicity is given for the sheaf of smooth functions, followed by the ( correct!) assertion that you have to repeat it with minor changes for, say, vector bundles. Moreover fine sheaves needn't even be mentioned if you follow this route.

$\endgroup$
1
  • 1
    $\begingroup$ Where in Grauert-Remmert do these results appear? $\endgroup$
    – Exterior
    Commented Aug 19, 2015 at 10:39
13
$\begingroup$

This answer takes a different point of view to that expressed in the body of your question, but is relevant to the question in the title.

A sheaf is called soft if any section over a closed subset of $X$ extends to a section over $X$. As the linked wikipedia article states, on a paracompact Hausdorff space, soft implies acyclic. The typical partitions of unity arguments in differential topology can be interpreted as using showing that sheafs of smooth functions, smooth sections of bundles, and so on, are soft. (One can always extend smooth functions locally from a closed set to a neighbourhood, and the partitions of unity allow one to patch these extensions.) Another way to phrase this is that fine implies soft .

$\endgroup$
8
$\begingroup$

Regarding point (2) in the question, I believe that Grothendieck's proof involves choosing a $f_i$ and $g_i$ in $A$ such that $\sum_i f_i g_i = 1$ (in other words, a cover of Spec $A$ by open sets of the form Spec $A_{f_i}$), computing the cohomology Cech-wise (which amounts to consider a Koszul complex), and then taking the limit over all such covers and using the Cech-to-sheaf-cohomology spectral sequence to conclude. So this is certainly an argument in the spirit of partitions of unity arguments.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .