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This is probably a dumb question.

Let $G$ be a connected complex reductive group and $X$ a compact Riemann surface. Consider a stable principal $G$-bundle $P$ on $X$. I am interested in how one uses deformation theory to prove that the tangent space at $P$ to the moduli space of principal $G$-bundles equals $H^1(X,\mathfrak g_P)$, where $\mathfrak g_P$ means the vector bundle associated to the adjoint representation of $G$.

I understand that a differential-geometric proof can be found, for example, in Kobayashi's book titled 'Differential geometry of complex vector bundles'. I am pretty sure there is a deformation-theoretic proof, but I failed at my attempts to find it. Does anyone know what is the right place to look for the answer? Also, what is a good reference of deformation theory in general? Thank you very much!

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    $\begingroup$ A natural route would be to start with nonabelian cohomology $H^1(X,G)$ classifying principal $G$-bundles: $G$-cocycles infinitesimally near to the one representing $P$ should be equivalent to $\mathfrak g_P$-cocycles. $\endgroup$ Commented Oct 25, 2016 at 3:31

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I don't know if this is what you're looking for, but here's a heuristic argument for this sort of thing being true in great generality. This should be a comment but it got long.

It's not hard to convince yourself that the tangent space to a map $f : X \to Y$, in the space of maps from $X$ to $Y$, whatever that means, is the space of sections of the pullback of the tangent bundle of $Y$ along $f$, or in other words $H^0(X, f^{\ast}(T_Y))$. (The generality in which you're willing to accept that something like this is true depends on the generality in which you're willing to talk about tangent spaces; here $X$ and $Y$ might be smooth manifolds or smooth varieties or something more general according to taste.)

In this situation $Y = BG$ is stacky and so its "tangent bundle" is also stacky; it's $\mathfrak{g}$, regarded as a representation of $G$ (and hence as a vector bundle on $BG$), but in degree $1$. The pullback of this tangent bundle along the classifying map of a $G$-bundle $f : X \to BG$ is the adjoint bundle of the $G$-bundle, but in degree $1$. And so its space of sections ends up being $H^1$ of the adjoint bundle.

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  • $\begingroup$ I like this but I want to understand the third paragraph better. Here is a question: Should I be thinking about BG as a simplicial manifold? $\endgroup$ Commented Oct 25, 2016 at 15:38
  • $\begingroup$ @Daniel: $BG$ is a stack; its functor of points sends a thing (smooth manifold, variety, scheme, whatever) to the groupoid of $G$-bundles on the thing. It can be presented by a simplicial thing, if you like. $\endgroup$ Commented Oct 25, 2016 at 18:07
  • $\begingroup$ It is also totally fine to think of BG as simplicial object (manifold, scheme, etc). Very easy to convert from this to the stack (functor taking values in groupoids): consider it's functor of points (taking values in simplicial sets) and take the 1-truncation of this. $\endgroup$ Commented Apr 12, 2017 at 23:24
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Let $k = \mathbb{C}$ be the field of complex numbers. Let $({\rm Art}_k)$ be the category of all Artin local $k$-algebra with residue field $A/\mathfrak{m} \cong k$. Let $E_H$ be a holomorphic (or equivalently, algebraic) principal $H$-bundle over $X$. For given any $A \in ({\rm Art}_k)$, the surjective ring homomorphism $A \longrightarrow A/\mathfrak{m} \cong k$ induces a closed embedding $i : X \hookrightarrow X_A := X\times {\rm Spec}(A)$. Consider the contravariant functor (called deformation functor)
$$\mathcal{D}_{E_H} : ({\rm Art}_k)^{\rm op} \longrightarrow ({\rm Set})$$ defined by setting $\mathcal{D}_{E_H}(A)$ to be the set of all equivalence classes $[F, \theta]$, where $F$ is a holomorphic principal $H$-bundle on $X_A = X\times_k{\rm Spec}(A)$ together with an isomorphism of principal $H$-bundles $\theta : i^*F \longrightarrow E_H$ over $X$. Two such pairs $(F,\theta)$ and $(F',\theta')$ are said to be equivalent if there is an isomorphism of principal $H$-bundles $\eta : F \longrightarrow F'$ over $X_A$ such that $\theta = \theta'\circ i^*(\eta)$.

Take $A = k[\epsilon]$, with $\epsilon^2 = 0$, i.e., $A = k[t]/(t^2)$. Let $(F,\theta) \in \mathcal{D}_{E_H}(k[\epsilon])$. Take any open subscheme $U$ of $X$. Then $U(\epsilon) := U\times_k {\rm Spec}(k[\epsilon])$ is an open subscheme of $X(\epsilon) := X\times_k{\rm Spec}(k[\epsilon])$. Then take an affine open cover $\{V_i := U_i(\epsilon)\}_{i \in I}$ of $X(\epsilon)$, and fix trivializations $F\vert_{V_i} \stackrel{f_i}{\longrightarrow} V_i\times H$. Then the transition functions for $F$ are of the form $g_{ij}+\epsilon\cdot h_{ij}$, where $g_{ij} : U_i\cap U_j \longrightarrow H$ are transition functions for $E_H = i^*F$, and $h_{ij} \in \Gamma(U_i\cap U_j, {\rm ad}(E_H))$ are sections of the adjoint vector bundle ${\rm ad}(E_H)$. Recall that, ${\rm Ad}(E_H) = E_H\times^H H$ is a group scheme of all principal $H$--bundle automorphisms of $E_H$ over $X$, with Lie algebra ${\rm ad}(E_H)$. The $H$--bundle automorphisms of $F$, which restricts to identity over the closed points $X \hookrightarrow X(\epsilon)$, is the adjoint vector bundle ${\rm ad}(E_H)$. Therefore, a section $s$ of ${\rm ad}(E_H)$ corresponds to the automorphism $1 + \epsilon s$ of $F$. Also if $s_1, s_2$ are two sections of ${\rm ad}(E_H)$, then $s_1 + s_2$ corresponds to the composite automorphism $(1+\epsilon s_1)(1+\epsilon s_2) = 1+\epsilon(s_1+s_2)$, since $\epsilon^2 = 0$. Now one can see that, these $h_{ij}$ defines a $1$--cocycle for ${\rm ad}(E_H)$, and hence defines an element of $H^1(X, {\rm ad}(E_H))$. The converse is also similar. Therefore, we have a canonical bijection $\mathcal{D}_{E_H}(k[\epsilon]) \cong H^1(X, {\rm ad}(E_H))$. Therefore, the space of all infinitesimal deformations of the principal $H$--bundle $E_H$ over $X$ is parametrized by $H^1(X, {\rm ad}(E_H))$.

Reference: I. Biswas and S. Ramanan, An Infinitesimal Study of the Moduli of Hitchin Pairs, doi: https://doi.org/10.1112/jlms/49.2.219.

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  • $\begingroup$ Can you explain with a little bit more of detail why The $H$-bundle automorphisms of $F$, which restricts to identity over the closed points $X\hookrightarrow X(\epsilon)$, is the adjoint vector bundle $ad(E_H)$ and therefore, a section $s$ of $ad(E_H)$ corresponds to the automorphism $1+\epsilon s$ of $ F$ ? $\endgroup$ Commented Sep 9, 2021 at 10:24

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