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If I have a known matrix A, is there a method to find a matrix B that share all the eigen vectors of Matrix A?

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Any analytic function of $A$ (including such diverse ones as $p(A),$ where $p$ is a polynomial, and $\exp(A)$) will work.

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    $\begingroup$ Moreover, if $A$ has all distinct eigenvalues then all solutions will be of that form. $\endgroup$ Commented Dec 19, 2016 at 16:21

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