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Let $k(n)$ denote the connected cover of Morava $K$-theory $K(n)$ at the prime $2$ and in particular $n=2$. It is known that $$ H^*(k(n)) = A//E(Q_n), $$ where $A$ is the Steenrod algebra and $Q_n$ is the Adams Margolis element which generates the exterior algebra $E(Q_n)$. In particular, $$ Q_2 = Sq^7 + Sq^6Sq^1 + Sq^5 Sq^2 + Sq^4 Sq^2 Sq^1.$$

If there is a spectrum X such that as an $A$-module $$ H^*(X) = A//E(Q_2),$$ then can we conclude that $X$ is weak equivalent to $k(2)$? In other words, is the homotopy type of $k(2)$ uniquely determined by its $A$-module structure?

[Note that my question is different from the results in the paper, where it is proved that as an $A_{\infty}$ ring spectrum $K(n)$ as well as $k(n)$ is essentially unique (correct me if I am wrong).]

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    $\begingroup$ Have you seen the more recent paper: arxiv.org/abs/1501.01448. Maybe what you want follows from their work. $\endgroup$ Commented Jan 19, 2016 at 12:53
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    $\begingroup$ Good reference, it seems plausible that the answer to my question is yes and it can be proved by tweaking the arguments of the above paper. $\endgroup$
    – Prasit
    Commented Jan 19, 2016 at 17:01

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