2
$\begingroup$

Suppose $A$ and $B$ are (complete) ordered sets. Suppose $R\subseteq A\times B$, and

$f(a)=\inf\{b : (a,b)\in R\}$

$g(b)=\inf\{a : (a,b)\in R\}$

then what can we call $f$ and $g$? Perhaps there is some standard terminology.

$\endgroup$
7
  • 2
    $\begingroup$ Antitone Galois connections? (At least in some cases.) $\endgroup$ Commented Nov 5, 2014 at 3:52
  • $\begingroup$ Note that $\mathbb{N}$ is not complete with respect to the usual ordering $\leq$ because $\mathbb{N}$ does not have a supremum. $\endgroup$ Commented Nov 5, 2014 at 8:43
  • $\begingroup$ Since he only takes infimums, he only needs lower semi-complete. $\endgroup$ Commented Nov 5, 2014 at 12:58
  • $\begingroup$ I don't know any standard terminology for this, but I would likely refer to $f$ as the lower boundary of $R$ and $g$ as the left boundary. If the order also had supremums, then there would also be a corresponding upper boundary and right boundary. $\endgroup$ Commented Nov 5, 2014 at 13:02
  • $\begingroup$ Thanks @JoelDavidHamkins in general that sounds good (in my case of interest $R$ is upward closed in the product order). $\endgroup$ Commented Nov 5, 2014 at 18:37

1 Answer 1

0
$\begingroup$

The maps $f,g$ constitute a Galois connection, but you have to take $\leq := \supseteq$ in both cases.

$\endgroup$
1
  • $\begingroup$ Or maybe $\ge $? $\endgroup$ Commented Nov 11, 2014 at 8:44

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .