13
$\begingroup$

Are there classes of infinite groups that admit Sylow subgroups and where the Sylow theorems are valid?

More precisely, I'm looking for classes of groups $\mathcal{C}$ with the following properties:

  • $\mathcal{C}$ includes the finite groups
  • in $\mathcal{C}$ there is a notion of Sylow subgroups that coincides with the usual one when restricted to finite groups
  • Sylow's theorems (or part of them) are valid in $\mathcal{C}$

An example of such a class $\mathcal{C}$ is given by the class of profinite groups.

Improve this question
$\endgroup$
3
  • 3
    $\begingroup$ Silly example: $\mathcal C$=profinite groups. Sylow subgroups = maximal closed pro-$p$ subgroups. One reason this is silly is that topological groups are not really a type of group. $\endgroup$
    – Will Sawin
    Commented Oct 23, 2012 at 5:12
  • 4
    $\begingroup$ @Will: the question mentions profinite groups at the end already. $\endgroup$
    – KConrad
    Commented Oct 23, 2012 at 5:53
  • 3
    $\begingroup$ Topologicallly finitely generated profinite groups have finite-index subgroups open, so the topology can be recovered from the group structure, and hence have an intrinsic notion of (pro-)p-subgroup. linkinghub.elsevier.com/retrieve/pii/S1631073X03003492 $\endgroup$
    – Ian Agol
    Commented Dec 30, 2022 at 17:25

6 Answers 6

Reset to default
7
$\begingroup$

A number of older papers by V.P. Platonov (in Russian, often followed by English translations) deal with periodic linear groups or linear algebraic groups in which the notions of Sylow theory make sense and where some results from the finite case actually generalize. One of the more substantial papers deals especially with conjugacy theorems:

The theory of algebraic linear groups and periodic groups. (Russian) Izv. Akad. Nauk SSSR Ser. Mat. 30 1966 573–620.

In other papers Platonov also works with classes of topological groups in a similar spirit.

P.S. Concerning sources, the long 1966 paper appears in an English translation (by the group theorist Kurt Hirsch) in volume 69 of the AMS Translations (Series 2), 1969; but this doesn't seem to be accessible online. There is a Google Scholar entry containing a full text PDF version of the Russian original here.

Improve this answer
$\endgroup$
7
$\begingroup$

You may also read Chapter 13 of Kurosh's book Theory of groups, volume 2. For instance, it contains a proof of Baer's theorem (cited by @Igor) which says that

all p-Sylow subgroups of a locally normal group are isomorphic.

Locally normal means periodic with finite conjugacy classes.

Improve this answer
$\endgroup$
5
$\begingroup$

Amalgams of finite groups provide another example. Let $A$ and $B$ be finite groups and let $C = A \cap B.$ Suppose that $P$ is a Sylow $p$-subgroup of $A$, and that $C$ contains a Sylow $p$-subgroup of $B.$ Then the amalgam $A*_{C}B$ has a unique conjugacy class of maximal finite $p$-subgroups, but is an infinite group as long as $C$ is proper in both $A$ and $B$. In fact, the process an then iterated to the case where $A$ and $B$ may themselves be amalgams of finite groups of this type, and so on. For general results on amalgams, see J.-P. Serre's book "Trees". For applications of this type of construction to fusion systems on finite $p$-groups, see two recent papers of mine in Journal of Algebra (Amalgams, blocks, weights, fusion systems and finite simple groups) and Transactions of the AMS (Reduction mod $q$ of fusion system amalgams).

Improve this answer
$\endgroup$
4
$\begingroup$

Well, the Wikipedia gives an example of a Sylow theorem, and there is more on this in notes Sylow theorems by Igusa. There is also the following paper of Baer:

Sylow theorems for infinite groups

Reinhold Baer

Source: Duke Math. J. Volume 6, Number 3 (1940), 598-614.

Improve this answer
$\endgroup$
3
$\begingroup$

The best reference for this subject is the book of Martyn Dixon: Locally finite groups and Sylow theory.

Improve this answer
$\endgroup$
2
$\begingroup$

In groups of finite Morley rank there is a Sylow theory for the prime $p=2$.

Improve this answer
$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .