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Prof. Valdes and Prof. Anderson studied factorization in commutative rings with zero divisors. I was wondering how similar factorization is in anticommutative rings with zero divisiors.

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  • $\begingroup$ Do you have a link to the article of Valdes & Anderson? Also do you really mean anti-commutative ($ab = -ab$) or 'just' non-commutative? $\endgroup$
    – Vincent
    Commented Jul 12, 2022 at 14:26
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    $\begingroup$ @Vincent I mean anticommutative. An example of anticommutative ring is R^3 under the cross product. $\endgroup$
    – Insulin69
    Commented Jul 12, 2022 at 14:31
  • $\begingroup$ researchgate.net/publication/… $\endgroup$
    – Insulin69
    Commented Jul 12, 2022 at 14:32
  • $\begingroup$ Okay. So they are naturally riddled with zero divisors as $x^2 = 0$ for all $x$ in such a ring. The most prominent examples are probably Lie algebras and exterior algebras $\bigwedge V$ for some vector space $V$. I would expect people have looked at factorization in those examples at least, but I don't know a reference $\endgroup$
    – Vincent
    Commented Jul 12, 2022 at 14:33
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    $\begingroup$ @Vincent Lie algebras aren't associative, so it's not clear what factorization would mean in that context (but maybe that's a good notion) and $\bigwedge V$ is not anticommutative in this strong sense because even wedges commute. $\endgroup$
    – Will Sawin
    Commented Jul 12, 2022 at 18:12

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