Suppose $T$ be a system of polynomials homogenous of degree 2 solvable over $\mathbb{R}$ and $\mathbb{Q}_p$ for all primes $p$. So, can we claim that $T$ is solvable over $\mathbb{Q}$? I think as of now there is no local global principle proven for system of polynomials, but could there be one?
$\begingroup$
$\endgroup$
6
-
3$\begingroup$ No. Look at Hasse principle. $\endgroup$– abxCommented Aug 27, 2021 at 10:15
-
$\begingroup$ Please look at my updated question. In case of homogenous polynomials of degree 2 is the answer still no? $\endgroup$– roydiptajitCommented Aug 27, 2021 at 10:52
-
10$\begingroup$ Restricting to homogeneous polynomials of degree $2$ (quadrics) doesn't help, because, as the answers to this question explain, every projective variety can be written (after a suitable embedding) as an intersection of quadrics. So the answer to your question is no, there is no local-global principle. (But I don't think the question is stupid and you shouldn't have been downvoted.) $\endgroup$– Gro-TsenCommented Aug 27, 2021 at 10:57
-
7$\begingroup$ In fact as soon as there are two equations of degree 2, the Hasse principle can fail. (With one, it's of course OK.) Given any elliptic curve E over Q whose Tate-Shafarevich group has 4-torsion, we can produce such a variety by taking a 4-torsion element, looking at the corresponding $E$-torsor, which fails the Hasse principle, and embedding it into $\mathbb P^3$ by a degree $4$ line bundle, where it will be the intersection of two quadrics. $\endgroup$– Will SawinCommented Aug 27, 2021 at 14:17
-
$\begingroup$ Thanks. @WillSawin $\endgroup$– roydiptajitCommented Aug 27, 2021 at 15:40
|
Show 1 more comment