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in the middle of working on some deformation related questions, I bumped into a question regarding finite type subalgebras of some completed algebras. I hope someone may know the answer, or may possibly be able to offer some ideas on it.

To make the question simple enough, let me take the following simplest case:

Let $k$ be a field and $k[[t]]$ be the ring of formal power series in 1 variable with the coefficients in $k$.

Suppose we have a finite type $k$-subalgebra $R \subset k[[t]]$, i.e. there exist some finitely many formal power series $f_1, \cdots, f_r$ in $t$ such that $R= k[f_1, \cdots, f_r]$.

Then, can one have a good way to compute the Krull dimension of $R$? Of course we know it is bounded by $r$ by Noether normalization, but I am asking whether we have some ways to "reduce" those $f_i$ in a sense.

Apparently, the case $r=1$ is trivial, so the question is interesting only when $r \geq 2$.

If all of $f_i$ are given by polynomials, then the question is very simple: the ring $R$ is contained in $k[x]$ and it is integral over $R$, so $R$ must be of dimension $1$.

However, when they are given by formal power series in general, I am not sure whether I can use some sorts of Weierstrass theorems here. Can one see any possible ways to handle these?

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    $\begingroup$ Krull dimension is just the transcendence degree of the ring. Unless you have some control over that, I don't think anything reasonable can be said. $\endgroup$
    – Mohan
    Commented May 18, 2021 at 14:58
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    $\begingroup$ Do you know about Neron desingularization? Does section 2.1 here arxiv.org/abs/1909.02903 help? $\endgroup$ Commented May 18, 2021 at 15:48
  • $\begingroup$ But yeah, as Mohan said above, it's hard to compute the transcendence degree of the field generated by some given list of formal power series. $\endgroup$ Commented May 18, 2021 at 16:15
  • $\begingroup$ @PiotrAchinger Thanks for suggesting your arXiv paper. I have used Neron desingularizations a few times, but it is first time to see your "spreadout" sort of version. Thanks for new insight! It does not solve what I was asking, but definitely it gives more room to think in a different way. $\endgroup$ Commented May 19, 2021 at 3:26

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