Timeline for Has the largest-to-rest eigenvalue ratio of real symmetric matrices been researched before?
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 8, 2021 at 14:31 | vote | accept | Anna | ||
| Aug 6, 2021 at 20:01 | review | Close votes | |||
| Aug 11, 2021 at 3:06 | |||||
| Aug 6, 2021 at 19:42 | comment | added | Alex M. | I’m voting to close this question because it is not clear what the OP is looking for. | |
| Aug 6, 2021 at 18:43 | answer | added | Jacob A | timeline score: 0 | |
| Jul 2, 2012 at 18:38 | comment | added | Federico Poloni | By the way, since I find it unusual that you reported two values: you know that the second ratio is $1+$ the first ratio, don't you? | |
| Jul 2, 2012 at 18:20 | answer | added | kjetil b halvorsen | timeline score: 0 | |
| Jul 2, 2012 at 18:19 | answer | added | Federico Poloni | timeline score: 3 | |
| Jun 19, 2012 at 12:18 | comment | added | Anna | @Stanislav: In my case, A is a function of a a lot of parameters, and takes ~0.1s to calculate (Monte Carlo simulation). I'm trying to optimise the ratio with regard to those parameters. But for this question, I'm just asking if some properties of these ratios have been investigated before. | |
| Jun 19, 2012 at 12:04 | comment | added | Stanislav | Then, it is not clear what the problem is. Why is it not possible to compute these eigenvalue ratios directly? | |
| Jun 18, 2012 at 20:35 | comment | added | Anna | @Stanislav: It is indeed. The only assumption on $A$ so far is that the expected energy of each sample series is equal, i.e. the 2-norm of each column of $A$ is roughly equal. | |
| Jun 18, 2012 at 20:08 | comment | added | Stanislav | @Anna: Which data are available? Is your matrix $B$ a sample covariance matrix? | |
| Jun 18, 2012 at 16:50 | answer | added | Igor Rivin | timeline score: 0 | |
| Jun 18, 2012 at 15:37 | comment | added | Anna | @Anthony: The matrix for my application originates from a noisy sampling process, so the denominator is almost surely positive. | |
| Jun 18, 2012 at 15:17 | comment | added | Anthony Quas | Not heard of this before, but what do you do to make sure the denominator isn't 0? | |
| Jun 18, 2012 at 14:43 | history | edited | Anna | CC BY-SA 3.0 |
added 79 characters in body; edited title; edited title
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| Jun 18, 2012 at 14:03 | history | asked | Anna | CC BY-SA 3.0 |