Timeline for Why a group of order $2^{m}\cdot p^{n}\cdot q^{t}$ is solvable?
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
S Jun 17, 2012 at 11:57 | vote | accept | Niki | ||
S Jun 17, 2012 at 11:57 | vote | accept | Niki | ||
S Jun 17, 2012 at 11:57 | |||||
Jun 17, 2012 at 11:56 | vote | accept | Niki | ||
S Jun 17, 2012 at 11:57 | |||||
Jun 17, 2012 at 9:09 | answer | added | R K | timeline score: 12 | |
Jun 17, 2012 at 8:36 | comment | added | user6976 | You do not need the Clasification. Probably there was a paper characterizing simple groups without elements of order 3. I did not find that paper, but found one where groups without elements of order 6 are characterized. So one can use already published results only. | |
Jun 17, 2012 at 8:32 | answer | added | user6976 | timeline score: 2 | |
Jun 17, 2012 at 8:30 | comment | added | S. Carnahan♦ | This follows from the classification of finite simple groups - in particular, the absence of 3 means you can narrow down the possibilities to the Suzuki series. | |
Jun 17, 2012 at 8:20 | comment | added | Yemon Choi | When you say "why", do you mean "if"? | |
Jun 17, 2012 at 7:57 | history | asked | Niki | CC BY-SA 3.0 |