Timeline for On the compactness of a certain chain topology [closed]

11 events

when toggle format	what		by	license	comment
Jun 19, 2012 at 7:48	vote	accept	K A Khan
Jun 16, 2012 at 20:22	history	closed	Andrés E. Caicedo Asaf Karagila♦ Dan Petersen Andreas Blass Chris Gerig		general reference
Jun 16, 2012 at 18:18	comment	added	Goldstern		Yes, I can prove it. This is certainly not a research-level question.
Jun 16, 2012 at 17:09	comment	added	Asaf Karagila♦		Karman, in $\{\varnothing,X\}$ you have that $\varnothing$ is the largest set.
Jun 16, 2012 at 14:20	answer	added	Joel David Hamkins		timeline score: 3
Jun 16, 2012 at 13:37	comment	added	Goldstern		Still no motivation; it looks like an exercise from a topology book. The space is compact iff there is a largest open set (excluding $X$ itself).
Jun 16, 2012 at 13:32	comment	added	K A Khan		@Edgar...since $\Lambda$ is linearly ordered, there must always exist some $\alpha\in\Lambda$ such that $A_\alpha\subset A_\lambda$ for all $\lambda\in\Lambda$
Jun 16, 2012 at 12:47	history	edited	K A Khan	CC BY-SA 3.0	added 69 characters in body
Jun 16, 2012 at 12:47	comment	added	Gerald Edgar		The family $I$ has a least nonempty element.
Jun 16, 2012 at 12:38	comment	added	Goldstern		What do you mean by "this chain topology"? The topology generated by the sets $A_\alpha$? What is the motivation for this question?
Jun 16, 2012 at 12:26	history	asked	K A Khan	CC BY-SA 3.0