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Oct 3 at 16:55 comment added Michael Hardy There is an argument based on cardinality that shows that such sets exist. If one says ONLY that because of cardinalities such a set exists, that appears non-constructive. But I suspect by looking at the arguments that show that the cardinalities of such-and-such sets are thus-and-so, one may be able to come closer to constructing an example. But this seems unlikely to qualify as "research-level" math.
Oct 30, 2021 at 22:20 history edited KConrad CC BY-SA 4.0
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Jun 13, 2012 at 15:41 history closed Zev Chonoles
Andreas Blass
Simon Thomas
Mark Meckes
George Lowther
too localized
Jun 13, 2012 at 15:41 answer added Gerald Edgar timeline score: 2
Jun 13, 2012 at 15:38 comment added Gerald Edgar @Chandra: But that is not what he is asking for...
Jun 13, 2012 at 15:09 comment added C.S. @jorge: Google search gives lot of good results. Here is one which I liked: unapologetic.wordpress.com/2010/04/24/…
Jun 13, 2012 at 14:14 comment added Zev Chonoles MathOverflow is for research-level questions only, see the FAQ: mathoverflow.net/faq#whatnot. Here is a thread on Math Stack Exchange where this topic is addressed: math.stackexchange.com/q/141017/264
Jun 13, 2012 at 14:06 history asked jorge vargas CC BY-SA 3.0