Timeline for Existence of points on varieties which avoid a given number field.
Current License: CC BY-SA 3.0
4 events
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Jun 12, 2012 at 7:32 | comment | added | Olivier Benoist | I edited my answer ; it should be easier to read. The equality L'=L\otimes_K K' comes by base change from the cartesian square involving \mathbb{A}^1_K, C,\mathbb{A}^1_{K'} and C_{K'}$. | |
Jun 12, 2012 at 7:26 | history | edited | Olivier Benoist | CC BY-SA 3.0 |
added 273 characters in body
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Jun 12, 2012 at 1:01 | comment | added | David Zureick-Brown | @Olivier: Thanks for the response! One question: why is L' = L \otimes_K K'? It seems like for K = Q, K' = Q(i), C = x^2 + y^2 + 1 = 0, and p' = (0,i), that L = L'. | |
Jun 11, 2012 at 23:35 | history | answered | Olivier Benoist | CC BY-SA 3.0 |