Timeline for Question on K3 Surface
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jun 10, 2012 at 19:00 | vote | accept | user24328 | ||
Jun 10, 2012 at 18:59 | comment | added | user24328 | Thanks Remke and Tony. Since $6H - 2E_{1} - \cdots -2E_{9} = 2F$, then what I say seems correct. Also, is it true that a pencil of lines in $E(1)$ given by $H$ with one base point pulls back to a pencil of genus two curves with two base points in $K3$? Since the line $H$ intersects the branch curve at $6$ points, it looks to upstairs we have genus two pencil. | |
Jun 10, 2012 at 18:36 | comment | added | Tony Pantev | Of course, you are right! I don't know what I was thinking. Somehow I did the calculation in my head without writing and, of course, I got it wrong. | |
Jun 10, 2012 at 9:38 | history | answered | Remke Kloosterman | CC BY-SA 3.0 |