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Jun 9, 2012 at 0:44 vote accept Hee Kwon Lee
Jun 8, 2012 at 22:49 comment added Dan Lee That's what I was getting at when I wrote "unless you..." It's not quite as simple as you say since the embedding is only unique up to isometry (and as you point out, requires positive curvature). My basic point is that you can't ask about happens in some given situation when you haven't properly set up the situation.
Jun 8, 2012 at 19:42 comment added Igor Rivin If the surface is positively curved, there is a unique embedding, so there is a completely canonical way to translate the flow into an extrinsic flow.
Jun 8, 2012 at 18:21 history answered Dan Lee CC BY-SA 3.0