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Jul 16, 2012 at 19:44 vote accept Asaf Karagila
Jun 9, 2012 at 18:23 history edited YCor CC BY-SA 3.0
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Jun 8, 2012 at 21:53 comment added YCor @Asaf: you mean, if $|X|^{\aleph_1}=|X|$ where $|X|$ is the cardinal of $X$; this is true if $|X|=2^\alpha$ with $\alpha\ge\aleph_1$ but this does not mean it is true for every cardinal large enough (at least I don't claim it).
Jun 8, 2012 at 17:43 comment added Asaf Karagila So this argument can be extended to "countable intersection" if $X$ is large enough, right?
Jun 8, 2012 at 16:16 history answered YCor CC BY-SA 3.0