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Feb 20, 2019 at 18:28 vote accept Stuart LaForge
Jun 8, 2012 at 16:43 comment added Anthony Quas I guess what I could have said to be more explicit is the theorem says low complexity implies rational or transcendental. Since rational was ruled out by the OP, we are left with transcendental.
Jun 8, 2012 at 5:39 comment added Harry Altman Neat theorem! A nitpick: This assumes the number is irrational, as otherwise rational numbers would be a counterexample.
Jun 7, 2012 at 15:49 comment added Anthony Quas PS: This would be just fine for any linear function of $n$. I'm not sure how this would work for anything else...
Jun 7, 2012 at 15:48 history answered Anthony Quas CC BY-SA 3.0