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Jun 5, 2012 at 14:39 comment added Misha @Andreas: Yes, of course, property T would require something else.
Jun 5, 2012 at 12:42 comment added Andreas Thom Maybe one can characterize property $\tau$ like this, but not property $(T)$.
Jun 5, 2012 at 0:36 history edited Misha CC BY-SA 3.0
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Jun 5, 2012 at 0:14 history answered Misha CC BY-SA 3.0