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Mar 2 at 16:41 history edited Martin Sleziak CC BY-SA 4.0
minor typos
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jan 25, 2016 at 10:56 comment added ACL @LaurentMoret-Bailly: The PhD Thesis of Hervé Perdry, hlombardi.free.fr/liens/TheseHervePerdry.pdf, took care of the question of constructive noetherianity by rewriting the definition of noetherian as “every increasing sequence pauses” (meaning “is not strictly increasing”).
Jun 2, 2012 at 14:08 comment added Martin Brandenburg You're right ... perhaps it doesn't work at all that way.
Jun 2, 2012 at 11:53 comment added Laurent Moret-Bailly One should be careful that the Dependent Choice Axiom is needed to prove that ``every increasing sequence terminates'' implies the existence of maximal elements. So, can the proof of Hilbert's theorem be arranged to take care of this?
Jun 1, 2012 at 15:17 comment added Martin Brandenburg Yes, but that's not really clever. The equivalence simplifies the problem right ahead. We shouldn't care about "Cohen's Theorem" (as the OP called it) at all.
Jun 1, 2012 at 14:59 comment added François G. Dorais You can get the result as stated without localization and quotient by adding the axioms $p_a$ for $a \in I$ and $\lnot p_b$ for $b \in S$. It looks like this does not affect the argument for finite consistency.
Jun 1, 2012 at 14:16 history answered Martin Brandenburg CC BY-SA 3.0