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May 30, 2012 at 17:12 comment added Andreas Blass The bound Arturo gave is not $O(p^{2n})$ but $O(p^{n^2})$.
May 30, 2012 at 16:38 comment added jason mfash So, is it true that the order of the aut group if $O(p^{2n})$?
May 30, 2012 at 16:33 vote accept jason mfash
May 30, 2012 at 16:30 answer added Arturo Magidin timeline score: 2
May 30, 2012 at 16:12 comment added Arturo Magidin See this previous question: mathoverflow.net/questions/68109/…. The order of the automorphism group of a group of order $p^n$ divides $(p^n-1)(p^n-p)\cdots(p^n-p^{n-1})$, and the bound is sharp, achieved by the elementary abelian $p$-group of rank $n$.
May 30, 2012 at 16:04 history asked jason mfash CC BY-SA 3.0