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Timeline for A sum of eigenvalues

Current License: CC BY-SA 3.0

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May 30, 2012 at 13:41 comment added Felix Goldberg Oh dear. Well, I had a feeling something was amiss. :)
May 30, 2012 at 12:24 comment added user11870 Yes, assume to be real. But what we want to prove is for any 0≤α≤1, $$\alpha \sum_{i=1}^r \max(0, \lambda_i(X))+(1-\alpha)\sum_{i=1}^r \max(0,\lambda_i(Y)) \leq \sum_{i=1}^r \max(0,\lambda_i(\alpha X+(1-\alpha)Y)). $$It is not trivial.
May 30, 2012 at 12:21 comment added Denis Serre @Felix. Your argument does not work because your $k$ depends upon $X$.
May 30, 2012 at 12:17 history answered Felix Goldberg CC BY-SA 3.0