Timeline for A sum of eigenvalues
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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May 30, 2012 at 13:41 | comment | added | Felix Goldberg | Oh dear. Well, I had a feeling something was amiss. :) | |
May 30, 2012 at 12:24 | comment | added | user11870 | Yes, assume to be real. But what we want to prove is for any 0≤α≤1, $$\alpha \sum_{i=1}^r \max(0, \lambda_i(X))+(1-\alpha)\sum_{i=1}^r \max(0,\lambda_i(Y)) \leq \sum_{i=1}^r \max(0,\lambda_i(\alpha X+(1-\alpha)Y)). $$It is not trivial. | |
May 30, 2012 at 12:21 | comment | added | Denis Serre | @Felix. Your argument does not work because your $k$ depends upon $X$. | |
May 30, 2012 at 12:17 | history | answered | Felix Goldberg | CC BY-SA 3.0 |