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May 11, 2013 at 9:45 answer added Pasha Zusmanovich timeline score: 1
May 25, 2012 at 3:57 answer added S. Carnahan timeline score: 2
May 24, 2012 at 20:07 comment added H. Arponen I'm assuming you just have the Lie algebra as commutation relations, maybe due to some symmetries of PDEs or such, and you're trying to determine if it corresponds to an affine Lie algebra?
May 24, 2012 at 16:34 history edited Eric O. Korman CC BY-SA 3.0
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May 24, 2012 at 15:34 answer added Jim Humphreys timeline score: 0
May 24, 2012 at 15:30 comment added Bill Cook However, an affine algebra $\hat{\mathfrak{g}}$ carries more information than just its Lie algebra structure. It has a built in gradation: $\hat{\mathfrak{g}}(n) = \mathfrak{g} \otimes t^n$. If you have this information, then your problem is trivial since $\hat{\mathfrak{g}}(0) = \mathfrak{g}$.
May 24, 2012 at 15:29 comment added Bill Cook This is what comes to mind: If you can find a cartan subalgebra (CSA), then $\hat{\mathfrak{g}}$ decomposes into root spaces. Take a maximal collection $\Delta$ of real roots such that the sum of any two elements of $\Delta$ is either in $\Delta$, 0, or not a root. Then the direct sum of the root spaces associated with the roots in $\Delta$ along with the CSA will give you $\mathfrak{g}$.
May 24, 2012 at 14:59 history asked Eric O. Korman CC BY-SA 3.0