Timeline for On the determination of a quadratic form from its isotropy group
Current License: CC BY-SA 3.0
7 events
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Dec 30, 2017 at 6:01 | history | edited | KConrad | CC BY-SA 3.0 |
Corrected a bad typographical error.
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May 26, 2012 at 2:14 | comment | added | Hugo Chapdelaine | So just to let you know that I posted a continuation of your "quite generous" post on quadratic forms in characteristic 2! see mathoverflow.net/questions/98003/… | |
May 24, 2012 at 22:45 | history | edited | KConrad | CC BY-SA 3.0 |
added 154 characters in body
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May 24, 2012 at 22:43 | comment | added | KConrad | Hugo: I edited my answer to discuss characteristic 2, but unfortunately the final result is inconclusive. I don't see how to make part e of my outline work in characteristic 2, but I don't have a specific counterexample to offer in characteristic 2 that would contradict what you are asking about. I suggest you post a new MO question that I indicate in the second to last paragraph of the updated answer for the people who are more familiar than I am with quadratic forms in characteristic 2. | |
May 24, 2012 at 22:39 | history | edited | KConrad | CC BY-SA 3.0 |
added 10722 characters in body
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May 24, 2012 at 13:22 | comment | added | Hugo Chapdelaine | Thanks Keith, it is good to have it for future reference! So what should one do in characteristic $2$ in order to save the statement? The naive definition for the inner product fails since we divide by $2$, moreover one should also replace the isotropy group by something a bit larger but what would be such a replacement... | |
May 24, 2012 at 0:29 | history | answered | KConrad | CC BY-SA 3.0 |