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Gerald Edgar
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See the two-sided Laplace transform: WIKIPEDIA
In $\int_{-\infty}^\infty e^{-st} f(t)\\,dt$$\int_{-\infty}^\infty e^{-st} f(t)\;dt$ write $z=e^{-s}$.

See the two-sided Laplace transform: WIKIPEDIA
In $\int_{-\infty}^\infty e^{-st} f(t)\\,dt$ write $z=e^{-s}$.

See the two-sided Laplace transform: WIKIPEDIA
In $\int_{-\infty}^\infty e^{-st} f(t)\;dt$ write $z=e^{-s}$.

Source Link
Gerald Edgar
  • 41.1k
  • 5
  • 125
  • 219

See the two-sided Laplace transform: WIKIPEDIA
In $\int_{-\infty}^\infty e^{-st} f(t)\\,dt$ write $z=e^{-s}$.