Timeline for the algebraic closure of strict henselian DVR
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Jun 8, 2018 at 9:14 | comment | added | Will Sawin | @zzy You are right, I have never once in my life remembered the name "Krasner's lemma". | |
Jun 7, 2018 at 23:29 | comment | added | Zhiyu | Thank you, what you say looks like Krasner's lemma. Before I found something related in the tilting approach to the proof of Fontaine-Winterberger theorem while he didn't give a proof and I come across this problem while searching on mathoverflow. | |
Jun 6, 2018 at 21:43 | comment | added | Will Sawin | @zzy I think always yes. The main thing to check is that every algebraic extension of $K(\hat{A})$ is defined over $K(A)$. To do that, you want to check that if you perturb the coefficients of the defining equation slightly, you get the same Galois extension. This is some famous theorem. | |
Jun 6, 2018 at 9:35 | comment | added | Zhiyu | Do $K(A)$ and $K(\hat A)$ have isomorphic absolute Galois groups? | |
May 21, 2012 at 3:57 | history | edited | Will Sawin | CC BY-SA 3.0 |
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May 20, 2012 at 6:40 | history | edited | Will Sawin | CC BY-SA 3.0 |
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May 20, 2012 at 6:23 | history | edited | Will Sawin | CC BY-SA 3.0 |
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May 20, 2012 at 5:57 | history | answered | Will Sawin | CC BY-SA 3.0 |