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Jul 22, 2023 at 19:46 comment added LSpice @inkspot, re, you can!
Jul 22, 2023 at 19:45 comment added LSpice @KevinBuzzard's hint referenced in the answer.
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jan 9, 2016 at 16:07 comment added Daniel Litt To get a scheme it suffices to find a vector bundle on $\overline{M_{g,n}}$ so that the stabilizer at every geometric point acts faithfully on its projectivization. I would expect a high-order jet bundle to work...
May 17, 2012 at 15:40 vote accept Ben Wieland
May 16, 2012 at 14:32 comment added Ben Wieland Does the non-tame inertia mean that they could have more general cohomology? But in practice, known cohomology classes, like Delta, don't violate restrictions on cohomology that could appear in schemes?
May 16, 2012 at 13:04 history edited Dan Petersen CC BY-SA 3.0
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May 16, 2012 at 11:25 comment added inkspot Ah, you intended (as I should have realized, sorry) "is finitely covered by" rather than "is a finite cover of".
May 16, 2012 at 11:12 comment added Dan Petersen @inkspot you're right, this seems much more delicate than I thought. Indeed every explicit construction of such a cover that I know of uses some kind of non-abelian level structure, which doesn't work over the integers. I have to run to a seminar but I'll edit the answer later.
May 16, 2012 at 10:16 comment added inkspot @Dan, please can you expand your remark that ${\overline M}_{g,n}$ is a finite cover of a smooth proper scheme (besides projective space)? As you say, it is a smooth Deligne-Mumford stack, but the inertia is not always tame, which, maybe, makes it not morally equivalent to a smooth proper scheme.
May 16, 2012 at 8:17 history edited Dan Petersen CC BY-SA 3.0
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May 16, 2012 at 8:10 history answered Dan Petersen CC BY-SA 3.0