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Apr 25, 2023 at 18:17 history edited LSpice CC BY-SA 4.0
Unicode -> TeX
Jul 10, 2012 at 17:31 vote accept Ioannis Souldatos
May 23, 2012 at 22:32 answer added David Milovich timeline score: 5
May 15, 2012 at 21:08 comment added Joel David Hamkins See en.wikipedia.org/wiki/Morass_(set_theory) for some information and a list of references.
May 15, 2012 at 19:11 comment added Ioannis Souldatos @ Joel David Hamkins: I think it is my turn to ask for a definition :). What is a gap-n morass?
May 15, 2012 at 15:11 comment added Joel David Hamkins I wonder if using a morass instead of a Kurepa tree might be a source of examples, since here one uses a system of small structures to approximate a large structure. The gap-n morass case is similar to your question, with a gap-n difference in the cardinals.
May 15, 2012 at 14:31 history edited Ioannis Souldatos CC BY-SA 3.0
Added definition of admits $(\kappa,\lambda)$.
May 15, 2012 at 14:25 comment added Ioannis Souldatos One more comment: The tree described in (1) is an Aronszajn tree. The family described in (2) is a Kurepa family. They are both very well-known objects among set-theorists. So, maybe there another object that can capture $(\alpha^{+3},\alpha)$, $(\alpha^{+4},\alpha)$ and so on.
May 15, 2012 at 14:22 comment added Ioannis Souldatos @Joel David Hamkins:Yes! A sentence $\sigma$ in a language with a unary predicate $P$ admits $(\kappa,\lambda)$, if $\sigma$ has a model $M$ such that $|M|=\kappa$ and $|P^M|=\lambda$. Of course, $\lambda\le\kappa$. So, not only we need a model of a specific size, but we need the predicate $P$ to have a specific size too.
May 15, 2012 at 13:13 comment added Joel David Hamkins Can you remind us what it means to "admit $(\kappa,\lambda)$"? Does it mean that the language has a predicate and you are asking for a model of size $\kappa$, where the predicate has size $\lambda$?
May 15, 2012 at 12:21 history edited Ioannis Souldatos
edited tags
May 15, 2012 at 12:14 comment added Ioannis Souldatos For the problem we are working on, we assume GCH. Nevertheless, I would be interested to hear what you have in mind.
May 15, 2012 at 4:36 comment added Péter Komjáth Does $2^\alpha\geq\alpha^{+n}$ qualify?
May 15, 2012 at 1:30 history asked Ioannis Souldatos CC BY-SA 3.0