Timeline for How to explain the condition (C) in critical point theory?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Nov 23, 2012 at 9:43 | comment | added | Thomas Rot | Thus if this condition does not hold, there is a sequence such that $|\grad f(x_i)|$->0 in S. The condition forces this sequence to have a limit, and the limit must be a critical point. | |
| Jun 14, 2012 at 5:39 | comment | added | Thomas Rot | There is no constant c>0 such that $||\nabla f||>c$ on $S$. | |
| Jun 14, 2012 at 2:26 | comment | added | economic | Thank you for your answer. But, I cann't still understand the meaning of this sentence of $\|\nabla f\|$ is not bounded away from zero". Is $\|\nabla f\|>0$ no bounded below, and verge to 0? | |
| May 14, 2012 at 7:34 | history | answered | Thomas Rot | CC BY-SA 3.0 |