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Timeline for left adjoint to restriction functor

Current License: CC BY-SA 3.0

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May 25, 2012 at 15:25 vote accept gholam
May 14, 2012 at 9:30 comment added Martin Brandenburg Yes, but this is a special case. When $X \setminus U$ is a disjoint union of opens, then it is open ...
May 14, 2012 at 9:24 comment added Yosemite Sam does the decomposition of QC(X) you described for clopens work for an infinite number of them? (I'm thinking of things like the Hilbert scheme which decomposes according to topological data of the parameterised subscheme, that's a countable disjoint union)
May 13, 2012 at 9:05 comment added Martin Brandenburg Well it is true when $U$ is a clopen subset of $X$, because then $\mathrm{Qcoh}(X) = \mathrm{Qcoh}(U) \times \mathrm{Qcoh}(X \setminus U)$. But otherwise probably it's only true in pathological cases. This is already visible in the affine case, say $X=\mathrm{Spec}(A)$ and $U=D(f)$ for some $f \in A$. When does $M \mapsto M_f$ preserve infinite products? Almost never.
May 13, 2012 at 8:30 comment added Yosemite Sam can we add some assumptions on U or X to make this true? (or is U=X the only case when this works?)
May 13, 2012 at 7:45 history answered Martin Brandenburg CC BY-SA 3.0