Timeline for Extremum under variations of a traceless matrix
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| Dec 24, 2009 at 22:12 | history | edited | Kim Morrison | CC BY-SA 2.5 |
added 70 characters in body
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| Dec 24, 2009 at 18:36 | comment | added | j.c. | Well if they are skew-symmetric, they are automatically traceless since their diagonal entries must be zero. I suspect that things may become a little clearer if you update your question with a more realistic functional that you're interested in. | |
| Dec 24, 2009 at 18:14 | comment | added | Pedro |
what if $X$ and $Y$ are skew-symmetric?
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| Dec 24, 2009 at 16:19 | comment | added | Pedro | Yep; seen like that you're right... The problem is that in all papers I read it is my first answer that appears!! (of course we have a real action ie: a functional, does it change something?) | |
| Dec 24, 2009 at 16:06 | history | answered | j.c. | CC BY-SA 2.5 |