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May 16, 2012 at 8:38 comment added Christian Liedtke ... of course, these effects were known to Igusa and Serre already, but these examples are maybe more explicit
May 16, 2012 at 8:37 comment added Christian Liedtke For example, William Lang ('Classical Godeaux Surface in Characteristic p', Math. Ann. 256, 419-427 (1981)) and Rick Miranda ('Nonclassical Godeaux Surfaces in Characteristic Five', Proc. AMS 91, 9-11 (1984)) address this. I'm not sure whether their examples are defined over the integers as they choose generic hyperplane sections, but maybe a computer search can establish this by hand? Miranda's examples also show explicitly that the Picard scheme need not be smooth - it becomes non-reduced for p=5 (in fact ${\rm Pic}^0$ is isomorphic to the non-reduced scheme $\mu_5$) ...
May 16, 2012 at 4:13 history edited Ben Wieland CC BY-SA 3.0
retraction
May 16, 2012 at 2:31 comment added Will Sawin Well then you should probably make that your answer to this question.
May 16, 2012 at 2:02 comment added Ben Wieland The Atiyah-Bott fixed point formula plus the obvious (conjectural) generalization of Fontaine's result shows that a smooth proper variety over Z must have trivial (pro-finite) fundamental group. Fontaine's proven theorem covers the case of dimension 1-3.
May 15, 2012 at 17:36 comment added Ben Wieland I just meant that since there is a standard conjecture that smooth and proper over Z implies rational, that nonnegative Kodaira dimension would be a more surprising counter-example. Fontaine's letter to Messing probably already forces rationality in dimension 2. ams.org/mathscinet-getitem?mr=1274493
May 15, 2012 at 3:31 comment added Will Sawin If there's some good reason why negative Kodaira dimension is necessary for smoothness, Castlenuovo's theorem on the generic fiber would imply that all dimension 2 proper smooth surfaces over Spec Z are rational, thus simply connected, pushing the minimum possible dimension of a counterexample up to 3.
May 15, 2012 at 2:41 comment added Will Sawin I was trying to construct a similar argument. I guessed the step "nonnegative Kodaira dimension => nonsmooth" purely on blind hope. Why is that true? (or implausibly untrue?) For n>1 all n monomials must have minimum degree p, else there are not enough monomials to avoid all the nonsingular points. You get the same computation for the Kodaira dimension nonnegative.
May 15, 2012 at 0:58 comment added Ben Wieland Oh, right, unbounded degree is bad for smoothness over $Z$. Since it doesn't work to produce a free action on a curve, it probably doesn't work to produce a free action on a simply connected space. More specifically, in the case $n=1$, avoiding the fixed point at $p$ requires an invariant monomial, thus minimum degree $p$, yielding nonnegative Kodaira dimension, making it implausible that it be smooth.
May 13, 2012 at 7:42 comment added Will Sawin Getting polynomials smooth over every $p$ might be tricky. It doesn't seem like the sort of thing that is impossible, but, for instance, you can't do it in dimension $2$ even with arbitrarily high degree. Do you think it would be possible to explicitly work out an example for some small $p$ and $n$, to show it exists?
May 13, 2012 at 5:59 comment added Ben Wieland Yes, $G$-invariant polynomials; or, equivalently, work downstairs. The degree is a free parameter. The higher degree, the larger the space to choose from, avoiding any problematic space of fixed dimension.
May 13, 2012 at 5:42 comment added Will Sawin What do you mean by "generic complete intersection"? What degree polynomials are you intersecting? Are they intended to be $G$-invariant polynomials?
May 13, 2012 at 4:39 history answered Ben Wieland CC BY-SA 3.0