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May 11, 2012 at 18:31 history edited OldMacdonaldHadaForm CC BY-SA 3.0
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May 11, 2012 at 18:30 comment added OldMacdonaldHadaForm Dear Jason Starr, thank you very much for your comment. I will rephrase the question to include only the case $k=1$, which is the one I was originarily interested in.
May 11, 2012 at 18:00 comment added Jason Starr Dear OMHF: Yes, there are choices of $\gamma$ such that $\gamma^k$ is zero. For instance, at least for many choices of $(g,n)$, there are nonconstant morphisms $u:\overline{M}_{g,n}\to Y$ with positive fiber dimension. If $\gamma$ is the pullback under $u$ of any divisor class from $Y$, then $\gamma^k$ will be zero for $k> \text{dim}(Y)$.
May 11, 2012 at 17:43 comment added Felipe Voloch Much better. The software running this site randomly bumps old unanswered questions from time to time. When it does so, it does under the name "MathOverflow", hence my request.
May 11, 2012 at 16:33 comment added OldMacdonaldHadaForm Do you like this one better?
May 11, 2012 at 15:34 comment added Felipe Voloch Pleasechange your username
May 11, 2012 at 14:45 history edited OldMacdonaldHadaForm CC BY-SA 3.0
added 5 characters in body; added 13 characters in body
May 11, 2012 at 14:40 history asked OldMacdonaldHadaForm CC BY-SA 3.0