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May 12, 2012 at 8:50 vote accept Gao 2Man
May 9, 2012 at 19:16 answer added John Klein timeline score: 3
May 9, 2012 at 18:01 comment added John Klein One can prove that BG∨BH is aspherical using Ganea's homotopy fiber sequence ΣG∧H → BG∨BH → BG×BH. The fiber and base are K(π,1)-spaces (the fiber is a wedge of circles), so therefore is the total space.
May 9, 2012 at 17:29 answer added Benjamin Steinberg timeline score: 3
May 9, 2012 at 17:22 answer added Charles Rezk timeline score: 14
May 9, 2012 at 14:38 comment added Fernando Muro I don't think Van Kampen's theorem suffices to prove that the first map is a weak equivalence. VK's theorem shows that it is an isomorphism on $\pi_1$, but an argument is needed to prove that the wedge of aspherical spaces is aspherical.
May 9, 2012 at 14:09 history asked Gao 2Man CC BY-SA 3.0