Timeline for Knight tour prime (conjecture)
Current License: CC BY-SA 3.0
7 events
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May 19, 2012 at 18:30 | comment | added | timur | @Eric: Thanks for the comments. Can you please elaborate a bit on how to treat 2? | |
May 19, 2012 at 9:15 | comment | added | Eric Naslund | @Timur: I quite like your second argument, you don't need to add this condition about $2$ by the way. | |
May 9, 2012 at 4:37 | history | edited | timur | CC BY-SA 3.0 |
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May 9, 2012 at 4:28 | comment | added | timur | @Roberto: The argument covers all cases. If I was considering only intermediate nodes, i.e., if I was trying to rule out Hamiltonian cycles instead of paths, it would have been enough to look at only the numbers $3$ and $5$. | |
May 9, 2012 at 2:19 | comment | added | Roberto Bosch Cabrera | @ timur:(update) Thank you, your argument is good, but you are considering that $3,5,7,11,13$ are intermediate or re-entry nodes for the hamiltonian path. What occurs if the path begin in $3$ for example?(similarly for $5,7,11,13$). | |
May 9, 2012 at 0:56 | history | edited | timur | CC BY-SA 3.0 |
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May 8, 2012 at 23:23 | history | answered | timur | CC BY-SA 3.0 |