Timeline for Weil reciprocity vs Artin reciprocity
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Apr 13, 2014 at 4:48 | vote | accept | Kiu | ||
May 9, 2012 at 20:33 | comment | added | Kiu | Thanks guys for the comments. What I meant above is what Dustin also pointed out. | |
May 8, 2012 at 19:42 | comment | added | David E Speyer | Oh I see. I was thinking we evaluate $f$ and $g$ first and then plug in, but, of course, doing it in the other order makes more sense. So Kiumars' definition is right even when $\mathrm{div}(f)$ and $\mathrm{div}(g)$ do overlap, without modification. My bad. | |
May 8, 2012 at 17:07 | comment | added | Dustin Clausen | David - doesn't this agree with what Kiumars wrote? Since $f^ag^{-b}$ has neither a zero nor a pole at p, it can be evaluated at $p$. | |
May 8, 2012 at 16:12 | comment | added | David E Speyer | The Weil symbol can be defined when $\mathrm{div}(f)$ and $\mathrm{div}(g)$ overlap. Let $\pi$ be a uniformizer at $p$ and write $f = f_0 \pi^b$ and $g = g_0 \pi^a$. Then $(f,g)_p = (-1)^{ab} f_0(p)^a g_0(p)^{-b}$. Exercise: This is independent of the choice of $\pi$. | |
May 8, 2012 at 15:13 | answer | added | Dustin Clausen | timeline score: 9 | |
May 8, 2012 at 13:55 | comment | added | Chandan Singh Dalawat | Strictly speaking, the Artin symbol makes sense only for (number fields and) function fields over finite fields. But there is version of Weil reciprocity for the latter, and your question would still make sense. | |
May 8, 2012 at 4:34 | comment | added | Chandan Singh Dalawat | Perhaps you need to assume that $\mathrm{div}(f)$ and $\mathrm{div}(g)$ are disjoint. | |
May 8, 2012 at 4:00 | history | asked | Kiu | CC BY-SA 3.0 |