Timeline for Positively curved metrics on $S^2\times S^2$
Current License: CC BY-SA 3.0
8 events
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May 6, 2012 at 21:51 | history | edited | Renato G. Bettiol | CC BY-SA 3.0 |
Corrected a problem, expanded Anton's comment and emphasized a few points
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May 6, 2012 at 21:40 | comment | added | Renato G. Bettiol | @Anton: Oh, OK, I think I got it. The OP was asking about warping any two positively curved metrics on $S^2$ (not the round metric), and these in general don't have any symmetries. So the warped products will not have symmetries either. I am editing my answer to reflect this. Thanks! | |
May 6, 2012 at 21:38 | comment | added | Renato G. Bettiol | @Anton: Thanks for your comment! Now I am a little confused: isn't it true that if $\phi$ is an isometry of $(M,g_M)$ and $\psi$ is an isometry of $(N,g_N)$ such that $f\circ\psi=\psi$, then $(\phi,\psi)$ is an isometry of $(M\times N,g_M+f g_N)$? In this way, there is an inclusion $Iso(M,g_M)\subset Iso(M\times N,g_M +f g_N)$, so if the first $S^2$ has the round metric, there would be a circle in the isometry group of the warped product $S^2\times_f S^2$? | |
May 6, 2012 at 20:52 | vote | accept | Hee Kwon Lee | ||
May 6, 2012 at 20:22 | comment | added | Anton Petrunin | Your second way is correct, BUT the first one is not. In general warped products do not admit an $S^1$ action AND Kleiner is not working here. | |
May 6, 2012 at 19:59 | vote | accept | Hee Kwon Lee | ||
May 6, 2012 at 20:52 | |||||
May 6, 2012 at 17:17 | history | edited | Renato G. Bettiol | CC BY-SA 3.0 |
Mention Robert Haslhofer's comment and improved formatting
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May 6, 2012 at 17:04 | history | answered | Renato G. Bettiol | CC BY-SA 3.0 |