Timeline for "Eigenvalue characters"
Current License: CC BY-SA 2.5
12 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Dec 24, 2009 at 0:02 | history | edited | Anton Geraschenko |
edited tags
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| Dec 23, 2009 at 21:05 | history | edited | user717 | CC BY-SA 2.5 |
added 2 characters in body
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| Dec 23, 2009 at 20:44 | comment | added | Pete L. Clark | @TJF: You're right that a nontrivial commutative linear group is not semisimple. From the context of the question, it seems fairly clear that the OP means the subgroup consisting of semisimple elements, equivalently "the Levi subgroup" or the maximal torus. | |
| Dec 23, 2009 at 20:16 | comment | added | Theo Johnson-Freyd | I'm a bit confused by your statement. With the definitions I'm used to, an abelian group cannot be semisimple, so if $G$ is abelian, $G_s = 1$. Alternately, all abelians are completely reducible. In any case, the semisimple groups I know have no nontrivial one-dimensional representations. Better would be to take a nonabelian group, and look at a maximal abelian subgroup; then any representation of the big group picks out characters of the subgroup, although in general those characters do not extend to (one-dimensional reps of) the big one. | |
| Dec 23, 2009 at 15:05 | comment | added | user717 | Done . | |
| Dec 23, 2009 at 15:04 | history | edited | user717 | CC BY-SA 2.5 |
added 82 characters in body
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| Dec 23, 2009 at 15:01 | comment | added | user2330 | You should add the reference to the previous question. Thanks. | |
| Dec 23, 2009 at 11:42 | vote | accept | user717 | ||
| Dec 23, 2009 at 11:41 | history | edited | Pete L. Clark | CC BY-SA 2.5 |
removed the word "stupid"
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| Dec 23, 2009 at 11:33 | answer | added | Pete L. Clark | timeline score: 5 | |
| Dec 23, 2009 at 11:18 | history | asked | user717 | CC BY-SA 2.5 |