Timeline for What makes a distance?
Current License: CC BY-SA 3.0
14 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| S Jul 23, 2013 at 12:59 | history | suggested | Hans-Peter Stricker | CC BY-SA 3.0 |
added "reflexive"
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| Jul 23, 2013 at 12:48 | review | Suggested edits | |||
| S Jul 23, 2013 at 12:59 | |||||
| May 8, 2012 at 2:41 | comment | added | kjetil b halvorsen | ¿Why is symmetry seen as natural? In some statistical contexts, a natural distance is asymmetric. An example is KL-divergence. This arises comparing distributions via likelihoodratio tests. I will only giv an example. Say we have two models: data from a normal distribution, or from a Cauchy distribution. Data from a Cauchy distribution will look very different from what you expect from a normal distribution, so a normal dist model will be easy to reject. But with data from a normal distribution, could be explained by a cauchy model, so the Cauchy model will be difficult to reject. Asymmetry! | |
| May 7, 2012 at 22:10 | answer | added | Hans-Peter Stricker | timeline score: 3 | |
| May 6, 2012 at 4:06 | answer | added | Suvrit | timeline score: 4 | |
| May 6, 2012 at 0:41 | answer | added | Aaron Meyerowitz | timeline score: 2 | |
| May 5, 2012 at 21:57 | comment | added | Hans-Peter Stricker | @Will: Thanks for this comment. In this vein I hope to get along. | |
| May 5, 2012 at 21:46 | comment | added | Will Sawin | Yes, you understand it correctly. One intuition is that the composition function represents the distance along a path. Then the distance along the path "a=> b => c => d" should be well-defined and should be equal to both sides of the associativity equation. | |
| May 5, 2012 at 21:29 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
added 40 characters in body
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| May 5, 2012 at 21:19 | history | edited | Hans-Peter Stricker | CC BY-SA 3.0 |
added 8 characters in body
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| May 5, 2012 at 21:07 | comment | added | Hans-Peter Stricker | How could I? All conditions are fulfilled by the standard $x+y$ alone, which gives rise to general metric space. | |
| May 5, 2012 at 20:57 | comment | added | Mariano Suárez-Álvarez | You are converging the the definition of uniform space... | |
| May 5, 2012 at 20:54 | history | asked | Hans-Peter Stricker | CC BY-SA 3.0 |